R 函数用于计算低于平均值的向量百分比

Question

我从网址中提取了一个csv文件并清理了它。我现在正在尝试创建一个函数，该函数接受两个输入，一个向量和一个数字，并告诉您向量中低于数字的值的百分比。向量将是 dfStates$jul2011，数字将是 dfStates$jul2011 的平均值。谁能指出我创建这个函数的正确方向？

readStates <- read.csv(url("http://www2.census.gov/programs-
surveys/popest/tables/2010-2011/state/totals/nst-est2011-01.csv"))  #Assign 
readStates
readStates[6:10] <- list(NULL) #Remove Variables x.4-x.8
readStates <- readStates[-c(1, 2, 3, 4, 5, 6, 7, 8, 60, 61, 62, 63, 64, 65, 
66, 67),] #Remove Rows
colnames(readStates)[1] <- "stateName"                                                       
#Fix Column Name  
colnames(readStates)[2] <- "base2010"                                                        
#Fix Column Name
colnames(readStates)[3] <- "base2011"                                                        
#Fix Column Name
colnames(readStates)[4] <- "jul2010"                                                         
#Fix Column Name
colnames(readStates)[5] <- "jul2011"                                                         
#Fix Column Name
dfStates <- 
as.data.frame(sapply(readStates,gsub,pattern="\.",replacement=""))              
#Remove Periods
dfStates <- as.data.frame(sapply(dfStates,gsub,pattern=",",replacement=""))                  
#Remove Commas  
dfStates$base2010 <- as.numeric(as.character(dfStates$base2010))                             
#Set as Numeric
dfStates$base2011 <- as.numeric(as.character(dfStates$base2011))                             
#Set as Numeric
dfStates$jul2010 <- as.numeric(as.character(dfStates$jul2010))                               
#Set as Numeric
dfStates$jul2011 <- as.numeric(as.character(dfStates$jul2011))                               
#Set as Numeric

Answer 1

嗨，

你可以取你的向量的意思

me<-mean(dfStates$jul2011)

然后将其放入不同的向量中，并计算小于平均值的值并计算值的数量。然后简单地计算百分比。

temp_vec<-dfStates$jul2011
len<-length(temp_vec)
temp_vec2<-temp_vec[temp_vec<me]
len_temp_vec2<-length(temp_vec2)
per<-(len_temp_vec2/len)*100
per