c编程读取多行并暂停，直到按键盘上的任何键为止

Question

我在C编程中非常新。我希望我能解释我的问题。我正在尝试开发一个程序来读取binary文件并转换为ASCII模式。没有任何问题。但是我要做的是询问用户，他/她想阅读多少行(例如20行(，然后仅显示二进制文件中的20行，然后询问用户按任何键继续。按下任何键后，然后再次显示该文件的下一个20行，依此类推。

我尝试使用getch()和getchar()，但仅适用于一行。

我以下代码可能有助于正确解释。请帮助我。预先感谢您。

#include<conio.h>
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
void header(); //Title function declaration
int main(int argc, char *argv[])
{
    FILE *fp; // File pointer declaration
    int i, j;
    unsigned char buffer[17]; // Trying to get value for 16 bites each
    fp = fopen(argv[1], "rb"); 
    if (argc == 1) { // Condition for if user didnt specify file name
        /* Assume that argv[0] is the program name */
        printf("usage: %s, <file_name>", argv[0]);
        return 0;
    }
    if (fp == NULL) { // condition if there is no file 
        fprintf(stderr, "File Open error (%s) , error = %d", argv[1], errno);
        exit(1);
    }
    else
    {
        header(); // Calling function header
        int read = 0;
        int address = 0;
        while ((read = fread(buffer, 1, 16, fp)) > 0)
        {
            printf("%08X", address); 
            printf(" ");
            address += 16;
            for (i = 0; i < read; i++)
            {
                if (i == 8) {
                    if (buffer[i] != NULL)
                        printf("-");
                }
                else {
                    printf(" ");
                }
                printf("%02X", buffer[i]);
            }
            int space = 16 - read;
            if (space != 0) {
                for (int x = 0; x < space; x++) {
                    int y = read + (x - buffer[x]);
                    printf("   ");
                }
            }
            printf("  ");
            for (j = 0; j < read; j++)
            {
                if (buffer[j] == NULL) {
                    printf(".");
                }
                if (isprint(buffer[j])) {
                    printf("%c", buffer[j]);
                    //fflush(stdin);
                }
                else {
                    if (buffer[j] != NULL) {
                        printf(".");
                    }
                }
            }
            printf("n");
        }
    }
    fclose(fp);
    return 0;
}
void header() {
    printf("ADDRESS  ");
    for (int i = 0X00; i <= 0X0F; i++)
    {
        if (i == 8) {
            printf("-");
        }
        else
        {
            printf(" ");
        }
        printf("%02X", i);
    }
    printf("  0123456789ABCDEF n");
    printf("----------------------------------------------------------------------------n");
}

和输出应该像 样品

Answer 1

您需要包围阅读和打印逻辑。

int read = 0;
int address = 0;
int numLines = 0;
printf("How many lines you want to print?");
scanf("%d", &numLines);
do {
       for(int i = 0; i<numLines; i++)
       {
                if ((read = fread(buffer, 1, 16, fp)) > 0)
                {
                      ....... //your printing logic here
                }
       }
       /*Flush input stream in case n left out*/
       int c;
       while ((c = getchar()) != 'n' && c != EOF) { }
       printf("press Any key to continuen");
       getchar();
 } while(read>0);