我需要在查询或临时表中生成列(不确定需要哪一个)
,这样我就可以有一个星期六的日期列表,在给定的日期范围内。
此列表将在连接中用于将记录与周关联。
我有什么选择?
样本输入:: 03/01/2013
: 04/30/2013
结果:
星期结束——03/02/2013——03/09/2013——03/16/2013——03/23/2013——03/30/2013——04/06/2013——04/13/2013——04/20/2013——04/27/2013——05/04/2013
当前代码:
create table #TBL7(YEAR INT, WEEKNUMBER INT, STARTDATE DATETIME, ENDDATE DATETIME)
begin
declare @startdate datetime
, @enddate datetime
, @ctr int
SET @startdate = CAST(2013 AS VARCHAR)+ '/01/01'
SET @enddate = CAST(2013 AS VARCHAR) + '/12/31'
SET @ctr = 0
WHILE @enddate >= @startdate
BEGIN
SET @ctr = @ctr + 1
INSERT INTO #TBL7
values(year(@startdate), @ctr, @startdate, @startdate + 6)
SET @startdate = @startdate + 7
END
end
select * from #TBL7
首先创建一个日历表。然后你有一个非常简单的查询:
select [Date]
from dbo.Calendar
where DayOfWeek = 'Saturday' and [Date] between '20130301' and '20130430'
日历表几乎总是处理日期的最佳方法,因为你是在处理数据,而不是代码,所以你可以看到它是正确的,没有需要维护的神秘代码。
这是Oracle代码。对不起,我不知道如何将此转换为SQL SERVER。应该不会很难。你所需要的只是使用合适的函数来代替to_date()和to_char(),并计算开始和结束日期之间的差异,例如(end_date-start_date)+1:
WITH data(r, some_date) AS
(
SELECT 1 r, to_date('03/01/2013', 'MM/DD/YYYY') some_date FROM dual
UNION ALL
SELECT r+1, to_date('03/01/2013', 'MM/DD/YYYY')+r FROM data WHERE r < 61 -- (end_date-start_date)+1
)
SELECT some_date
, To_Char(some_date, 'DY') wk_day
FROM data
WHERE To_Char(some_date, 'DY') = 'SAT'
/
SOME_DATE WK_DAY
--------------------
3/2/2013 SAT
3/9/2013 SAT
3/16/2013 SAT
3/23/2013 SAT
3/30/2013 SAT
4/6/2013 SAT
4/13/2013 SAT
4/20/2013 SAT
4/27/2013 SAT
应该可以:
WITH cteWeeks (WeekEnding) As
(
-- Find the Saturday of the first week.
-- Need to allow for different DATEFIRST settings:
SELECT
CASE
WHEN DatePart(dw, DateAdd(day, @@datefirst, @StartDate)) = 7 THEN @StartDate
ELSE DateAdd(day, 7 - DatePart(dw, DateAdd(day, @@datefirst, @StartDate)), @StartDate)
END
UNION ALL
SELECT
DateAdd(day, 7, WeekEnding)
FROM
cteWeeks
WHERE
WeekEnding < @EndDate
)
SELECT
WeekEnding
FROM
cteWeeks
;
http://www.sqlfiddle.com/!3/d41d8/12095