有时,使用 Python 中的内置函数将两个列表组合成一个元组很方便zip
。如何在 Go 中类似地做到这一点?
例如:
>>> zip ([1,2],[3,4])
[(1,3), (2,4)]
你可以做这样的事情,你给元组类型一个名字:
package main
import "fmt"
type intTuple struct {
a, b int
}
func zip(a, b []int) ([]intTuple, error) {
if len(a) != len(b) {
return nil, fmt.Errorf("zip: arguments must be of same length")
}
r := make([]intTuple, len(a), len(a))
for i, e := range a {
r[i] = intTuple{e, b[i]}
}
return r, nil
}
func main() {
a := []int{1, 2, 3, 4, 5, 6, 7, 8, 9, 0}
b := []int{0, 9, 8, 7, 6, 5, 4, 3, 2, 1}
fmt.Println(zip(a, b))
}
或者对元组使用未命名的类型,如下所示:
package main
import "fmt"
func zip(a, b []int) ([][3]int, error) {
if len(a) != len(b) {
return nil, fmt.Errorf("zip: arguments must be of same length")
}
r := make([][4]int, len(a), len(a))
for i, e := range a {
r[i] = [2]int{e, b[i]}
}
return r, nil
}
func main() {
a := []int{1, 2, 3, 4, 5, 6, 7, 8, 9, 0}
b := []int{0, 9, 8, 7, 6, 5, 4, 3, 2, 1}
fmt.Println(zip(a, b))
}
最后,这里有一个软通用的方法:
package main
import (
"fmt"
"reflect"
)
func zip(a, b, c interface{}) error {
ta, tb, tc := reflect.TypeOf(a), reflect.TypeOf(b), reflect.TypeOf(c)
if ta.Kind() != reflect.Slice || tb.Kind() != reflect.Slice || ta != tb {
return fmt.Errorf("zip: first two arguments must be slices of the same type")
}
if tc.Kind() != reflect.Ptr {
return fmt.Errorf("zip: third argument must be pointer to slice")
}
for tc.Kind() == reflect.Ptr {
tc = tc.Elem()
}
if tc.Kind() != reflect.Slice {
return fmt.Errorf("zip: third argument must be pointer to slice")
}
eta, _, etc := ta.Elem(), tb.Elem(), tc.Elem()
if etc.Kind() != reflect.Array || etc.Len() != 2 {
return fmt.Errorf("zip: third argument's elements must be an array of length 2")
}
if etc.Elem() != eta {
return fmt.Errorf("zip: third argument's elements must be an array of elements of the same type that the first two arguments are slices of")
}
va, vb, vc := reflect.ValueOf(a), reflect.ValueOf(b), reflect.ValueOf(c)
for vc.Kind() == reflect.Ptr {
vc = vc.Elem()
}
if va.Len() != vb.Len() {
return fmt.Errorf("zip: first two arguments must have same length")
}
for i := 0; i < va.Len(); i++ {
ea, eb := va.Index(i), vb.Index(i)
tt := reflect.New(etc).Elem()
tt.Index(0).Set(ea)
tt.Index(1).Set(eb)
vc.Set(reflect.Append(vc, tt))
}
return nil
}
func main() {
a := []int{1, 2, 3, 4, 5, 6, 7, 8, 9, 0}
b := []int{0, 9, 8, 7, 6, 5, 4, 3, 2, 1}
c := [][2]int{}
e := zip(a, b, &c)
if e != nil {
fmt.Println(e)
return
}
fmt.Println(c)
}
要zip
一定数量的切片[]int
列表,
package main
import "fmt"
func zip(lists ...[]int) func() []int {
zip := make([]int, len(lists))
i := 0
return func() []int {
for j := range lists {
if i >= len(lists[j]) {
return nil
}
zip[j] = lists[j][i]
}
i++
return zip
}
}
func main() {
a := []int{1, 2, 3}
b := []int{4, 5, 6}
c := []int{7, 8, 9, 0}
iter := zip(a, b, c)
for tuple := iter(); tuple != nil; tuple = iter() {
fmt.Println("tuple:", tuple)
}
}
输出:
元组: [1 4 7]元组: [2 5 8]元组: [3 6 9]
Go 1.18
通过对类型参数的支持,您可以编写一个压缩任意两个切片的 zip 函数。
您可以声明一个可以容纳任意两种类型的元组结构,如下所示:
type Pair[T, U any] struct {
First T
Second U
}
还有拉链功能。它可以像这样简单:
func Zip[T, U any](ts []T, us []U) []Pair[T,U] {
if len(ts) != len(us) {
panic("slices have different length")
}
pairs := make([]Pair[T,U], len(ts))
for i := 0; i < len(ts); i++ {
pairs[i] = Pair[T,U]{ts[i], us[i]}
}
return pairs
}
用法示例:
func main() {
ts := []uint64{100, 200, 300}
us := []string{"aa", "bb", "cc"}
p := Zip(ts, us)
fmt.Println(p)
// prints [{100 aa} {200 bb} {300 cc}]
}
您还可以修改上述函数以压缩不同长度的切片,方法是将较短切片的Pair
字段保留为其零值:
func ZipDiff[T, U any](ts []T, us []U) []Pair[T, U] {
// identify the minimum and maximum lengths
lmin, lmax := minmax(len(ts), len(us))
pairs := make([]Pair[T, U], lmax)
// build tuples up to the minimum length
for i := 0; i < lmin; i++ {
pairs[i] = Pair[T, U]{ts[i], us[i]}
}
if lmin == lmax {
return pairs
}
// build tuples with one zero value for [lmin,lmax) range
for i := lmin; i < lmax; i++ {
p := Pair[T, U]{}
if len(ts) == lmax {
p.First = ts[i]
} else {
p.Second = us[i]
}
pairs[i] = p
}
return pairs
}
例:
func main() {
ts := []uint64{100}
us := []string{"aa", "bb", "cc", "dd", "ee"}
p := ZipDiff(ts, us)
fmt.Println(p)
// prints [{100 aa} {0 bb} {0 cc} {0 dd} {0 ee}]
q := ZipDiff(us, ts)
fmt.Println(q)
// prints [{aa 100} {bb 0} {cc 0} {dd 0} {ee 0}]
}
操场上可用的代码和minmax
助手功能:https://go.dev/play/p/jpChqsl_GNl
如果你需要zip
函数的结果是map
,这可以通过comparable
约束来完成
func zip[K comparable, V any](a []K, b []V) map[K]V {
c := make(map[K]V)
for i := 0; i < len(a); i++ {
c[a[i]] = b[i]
}
return c
}