JSON 字符串到 PHP 数组 NULL

Question

这是我的代码：

    var_dump(json_decode($data['event']->options['meals']['options'][0]['option'], true));
    echo '<br />';echo '<br />';
    var_dump($data['event']->options['meals']['options'][0]['option']);
    echo '<br />';echo '<br />';
    var_dump(json_decode('[{"name":"Petit Tenderloin","description":"Wrapped in Apple Wood Bacon, borsoun whipped mashed potatoes, roasted baby vegetable, with sun dried cherry sauce. "},{"name":"Chicken Piccatta","description":"In lemon caper sauce, served with a timbal of wild rice and vegetables. "}]', true));

这是我的输出：

NULL
string(279) "[{"name":"Petit Tenderloin","description":"Wrapped in Apple Wood Bacon, borsoun whipped mashed potatoes, roasted baby vegetable, with sun dried cherry sauce. "},{"name":"Chicken Piccatta","description":"In lemon caper sauce, served with a timbal of wild rice and vegetables. "}]"
array(2) { [0]=> array(2) { ["name"]=> string(16) "Petit Tenderloin" ["description"]=> string(115) "Wrapped in Apple Wood Bacon, borsoun whipped mashed potatoes, roasted baby vegetable, with sun dried cherry sauce. " } [1]=> array(2) { ["name"]=> string(16) "Chicken Piccatta" ["description"]=> string(72) "In lemon caper sauce, served with a timbal of wild rice and vegetables. " } }

为什么当我输入字符串文字时，我得到了正确的数组，但是当我传入一个变量时，我得到了 NULL？我觉得我错过了一些超级简单的东西......

编辑：找出原因看起来变量有一个换行符，自然不会显示在 HTML 中。看起来新的行字符中断json_decode...

除了删除新行之外，有谁知道解决方法吗？（如果可以的话，我宁愿把它们留在里面）

Answer 1

确保数组在var_dump其内容的第一行上有数据。 我无法重现您的错误。

我的代码：

<?php
$data['event']->options['meals']['options'][0]['option'] = '[{"name":"Petit Tenderloin","description":"Wrapped in Apple Wood Bacon, borsoun whipped mashed potatoes, roasted baby vegetable, with sun dried cherry sauce. "},{"name":"Chicken Piccatta","description":"In lemon caper sauce, served with a timbal of wild rice and vegetables. "}]';
var_dump(json_decode($data['event']->options['meals']['options'][0]['option'], true));
echo '<br />';echo '<br />';
var_dump($data['event']->options['meals']['options'][0]['option']);
echo '<br />';echo '<br />';
var_dump(json_decode('[{"name":"Petit Tenderloin","description":"Wrapped in Apple Wood Bacon, borsoun whipped mashed potatoes, roasted baby vegetable, with sun dried cherry sauce. "},{"name":"Chicken Piccatta","description":"In lemon caper sauce, served with a timbal of wild rice and vegetables. "}]', true));

？>

这是它为我产生的输出：

array(2) {
  [0] =>
  array(2) {
    'name' =>
    string(16) "Petit Tenderloin"
    'description' =>
    string(115) "Wrapped in Apple Wood Bacon, borsoun whipped mashed potatoes, roasted baby vegetable, with sun dried cherry sauce. "
  }
  [1] =>
  array(2) {
    'name' =>
    string(16) "Chicken Piccatta"
    'description' =>
    string(72) "In lemon caper sauce, served with a timbal of wild rice and vegetables. "
  }
}
<br /><br />
string(278) "[{"name":"Petit Tenderloin","description":"Wrapped in Apple Wood Bacon, borsoun whipped mashed potatoes, roasted baby vegetable, with sun dried cherry sauce. "},{"name":"Chicken Piccatta","description":"In lemon caper sauce, served with a timbal of wild rice and vegetables. "}]"
<br /><br />
array(2) {
  [0] =>
  array(2) {
    'name' =>
    string(16) "Petit Tenderloin"
    'description' =>
    string(115) "Wrapped in Apple Wood Bacon, borsoun whipped mashed potatoes, roasted baby vegetable, with sun dried cherry sauce. "
  }
  [1] =>
  array(2) {
    'name' =>
    string(16) "Chicken Piccatta"
    'description' =>
    string(72) "In lemon caper sauce, served with a timbal of wild rice and vegetables. "
  }
}

Answer 2

未转义的新行字符将中断json_decode，因为这不是有效的 JSON。

上一个关于 JSON 中转义换行符的问题。

查看无眼睑的答案，以保持换行符。 简短的版本是您需要转义它们，例如：

$text = str_replace("n", "\n", $text);

或者，您可能希望将换行符替换为 <br> ，转义换行符以便在浏览器中呈现。

你有GIGO。 不确定您是否在控制输入，但如果是，那么您应该使用 json_encode 在前端对其进行转义，这将自动转义（从而保留）换行符。