pandas.dateTimeIndex.snap时间戳到左发生的频率

Question

我想具有相同的功能，但使用左出现的频率而不是最近。

这是我正在尝试的：

date = pd.date_range('2015-01-01', '2015-12-31')
week_index = pd.DatetimeIndex.snap(date, 'W-MON')
week_index
DatetimeIndex(['2014-12-29', '2015-01-05', '2015-01-05', '2015-01-05',
               '2015-01-05', '2015-01-05', '2015-01-05', '2015-01-05',
               '2015-01-12', '2015-01-12',
               ...
               '2015-12-21', '2015-12-21', '2015-12-21', '2015-12-28',
               '2015-12-28', '2015-12-28', '2015-12-28', '2015-12-28',
               '2015-12-28', '2015-12-28'],
              dtype='datetime64[ns]', length=365, freq='W-MON')

，尽管它输出了valueerror：

似乎地板应该做到这一点

week_index = pd.DatetimeIndex.floor(date, 'W-MON')
---------------------------------------------------------------------------
ValueError                                Traceback (most recent call last)
<ipython-input-40-a053b5230ee3> in <module>()
----> 1 week_index = pd.DatetimeIndex.floor(date, 'W-MON')
C:ProgramDataAnaconda3libsite-packagespandastseriesbase.py in floor(self, freq)
     99     @Appender(_round_doc % "floor")
    100     def floor(self, freq):
--> 101         return self._round(freq, np.floor)
    102 
    103     @Appender(_round_doc % "ceil")
C:ProgramDataAnaconda3libsite-packagespandastseriesbase.py in _round(self, freq, rounder)
     79 
     80         from pandas.tseries.frequencies import to_offset
---> 81         unit = to_offset(freq).nanos
     82 
     83         # round the local times
C:ProgramDataAnaconda3libsite-packagespandastseriesoffsets.py in nanos(self)
    510     @property
    511     def nanos(self):
--> 512         raise ValueError("{0} is a non-fixed frequency".format(self))
    513 
    514 
ValueError: <Week: weekday=0> is a non-fixed frequency

Answer 1

我在pandas snap源代码中找到解决方案：

使用回滚：

from pandas.tseries.frequencies import to_offset  
freq = to_offset('W-MON')  
date.map(freq.rollback)