如何快速获取经纬度或gps数据，而我们在室内的安卓手机

Question

我试图通过GPS从安卓手机获得纬度和经度信息，当我在户外或直接在天空下时，我能够立即获得这些值，但当我在室内或房间内时，它需要一分钟多的时间才能获得这些值。当我在房间内使用我的应用程序时，谁能帮助我快速获得这个值?

我使用以下代码来获取值:

LocationManager locManager;
locManager = (LocationManager)getSystemService(Context.LOCATION_SERVICE);
locManager.requestLocationUpdates(LocationManager.GPS_PROVIDER,1000L,500.0f,
                                  locationListener);
Location location = locManager.getLastKnownLocation(LocationManager.GPS_PROVIDER);

和

private final LocationListener locationListener = new LocationListener() {
    public void onLocationChanged(Location location) {
    EditText myLocationText = (EditText)findViewById(R.id.editText1);
    EditText myLocationText1 = (EditText)findViewById(R.id.editText2);
    String latString = "";
    String LongString = "";
    if (location != null) {
        double lat = location.getLatitude();
        double lng = location.getLongitude();
        latString = "" + lat;
        LongString ="" + lng;

    } else {
        latString = "No location found";
        LongString = "No location found";
           }
     myLocationText.setText(""+ latString);
     myLocationText1.setText(""+ LongString);
}

除了使用LocationManager之外，还有其他方法可以获得GPS值吗??

Answer 1

你可以得到最后一个已知的位置，而且相当快:

/**
 * Gets the last known location.
 *
 * @param locationManager the location manager
 * @return the last known location
 */
public static Location getLastKnownLocation(LocationManager locationManager)
{
    Location bestResult = null;
    float bestAccuracy = 10000;
    long bestTime = 0;
    List<String> matchingProviders = locationManager.getAllProviders();
    for (String provider: matchingProviders) {
        Log.d("LOCATION", "Provider: " + provider);
        Location location = locationManager.getLastKnownLocation(provider);
        Log.d("LOCATION", "Location found? "+ (location==null?"NO":"YES"));
        if (location != null) {
            float accuracy = location.getAccuracy();
            long time = location.getTime();
            Log.d("LOCATION", "Acc: "+ String.valueOf(accuracy) + " -- Time: " + String.valueOf(time));
            if ((time > minTime && accuracy < bestAccuracy)) {
                bestResult = location;
                bestAccuracy = accuracy;
                bestTime = time;
            }
            else if (time < minTime && 
                    bestAccuracy == Float.MAX_VALUE && time > bestTime){
                bestResult = location;
                bestTime = time;
            }
        }
    }
    Log.d("LOCATION", "BEST FOUND? "+ (bestResult==null?"NO":"YES"));
    return bestResult;
}

Answer 2

您可以在LocationManager中使用以下方法获得设备的最后已知位置，这是最后在系统范围内找到的位置。

这个方法是关键:

Location lastKnownLocation = locationManager.getLastKnownLocation(locationProvider);

查看详细信息获取用户位置

Answer 3

如果您在室内，您最好使用LocationManager.NETWORK_PROVIDER，因为您不太可能在室内获得信号。您也可以使用getLastKnownLocation()，但这可能不存在或过时。

Answer 4

如果你想在一个房间里获得位置，gps提供商是缓慢的。你可以试着修改:

locManager.requestLocationUpdates(LocationManager.GPS_PROVIDER,1000L,500.0f,
                                  locationListener);
Location location = locManager.getLastKnownLocation(LocationManager.GPS_PROVIDER);

由:

locManager.requestLocationUpdates(LocationManager.NETWORK_PROVIDER,1000L,500.0f,
                                      locationListener);

您将在'public void onLocationChanged(location location)'方法中接收location

Answer 5

我使用网络提供商来获取坐标，它总是更快的房子里的客厅。但当我在地下室区域尝试同样的操作时，它根本无法获取坐标，尽管我等了差不多几分钟。

注意:我可以从地下室打电话，我也可以浏览…