动态php后台中的目录错误

Question

我试图通过从数据库中获取一个目录和内联样式来为每个div加载一个单独的图像

<div class="query">
    <?php
    if ($type == "category") {
    $query = "SELECT * FROM shopItems WHERE category = '" . $_GET['query'] ."'";
    $result = mysqli_query($con, $query);
    $i = 0;
    while ($row = mysqli_fetch_array($result)) {
        $i = $i + 1;
        $url = '../img/'.$row['imgSRC'];
        if ($i % 2 != 0) {
            if ($i != 1) {
                echo '</div>';
            }
            echo '<div class="queryRow"><div class="item" style"background:url(' . $url . ') no-repeat; background-size:contain;">' . $row['productName'] . '</div>';
        } else {
            echo '<div class="item" style"background:url(' . $url . ') no-repeat; background-size:contain;">' . $row['productName'] . '</div>';
        }
    }
    echo "</div>";
    ?>
</div>

我的问题是，当加载页面时，$url变量中的斜杠（"/"）会被空格替换，因此浏览器认为给定了一个无效的url，我该如何解决这个问题？

Answer 1

尝试

style = "background:url(' . $url . ') no-repeat; background-size:contain;"

而不是

style"background:url(' . $url . ') no-repeat; background-size:contain;"

echo '<div class="item" style = "background:url(' . $url . ') no-repeat; background-size:contain;">' . $row['productName'] . '</div>';