我是 Bazel 的新手,正在学习它的构建工作,目前我正在尝试从 Maven 项目中使用 bazel 构建,请告诉我如何使其工作,谢谢。
这是我尝试定义的工作区文件:
maven_jar(
name = "junit",
artifact = "junit:junit:3.8.1",
)
maven_jar(
name = "log4j1",
artifact = "org.apache.logging.log4j:log4j-core:2.6.2",
)
maven_jar(
name = "log4j2",
artifact = "org.apache.logging.log4j:log4j-api:2.6.2",
)
.....
这是我尝试定义的构建文件:
package(default_visibility = ["//visibility:public"])
java_binary(
name = "everything",
srcs = glob(["src/main/java/**/*.java"]),
resources = glob(["src/main/resources/**"]),
main_class = "src/main/java/com/test/test/test/App",
deps = [
"@junit//jar",
"@log4j1//jar",
"@log4j2//jar",
"@jackson//jar",
"@jsonsimple//jar",
"@commonsdbutils//jar",
"@commons//jar",
"@guava//jar",
"@poi//jar"],
)
这是我得到的 Bazel 构建结果:
mbp:bazel_test me$ bazel build //:everything
INFO: Analysed target //:everything (1 packages loaded).
INFO: Found 1 target...
ERROR: /Users/me/git/test/test/BUILD:4:1: Building everything-class.jar (104 source files) failed (Exit 1)
src/main/java/com/test/test/test/Testapp.java:13: error: cannot find symbol
import org.apache.poi.ss.usermodel.Cell;
^
symbol: class Cell
location: program package org.apache.poi.ss.usermodel
.....
Target //:everything failed to build
我在这里看到两个问题:
main_class
属性应使用点而不是斜杠:
java_binary(
name = "everything",
srcs = glob(["src/main/java/**/*.java"]),
main_class = "src.main.java.com.test.test.test.App",
...
- poi 罐子里没有
org.apache.poi.ss.usermodel.Cell
类。
找到罐子的名称:
$ bazel query --output=build @poi//jar
...
java_import(
name = "jar",
visibility = ["//visibility:public"],
jars = ["@poi//jar:poi-ooxml-3.9.jar"],
srcjar = "@poi//jar:poi-ooxml-3.9-sources.jar",
)
包的位置是 $(bazel info output_base)/external/poi
,现在我们知道(从上面bazel query
输出中的 srcs
属性(该文件被称为 poi-ooxml-3.9.jar
:
$ unzip -l $(bazel info output_base)/external/poi/jar/poi-ooxml-3.9.jar | grep "org.apache.poi.ss.usermodel"
0 2012-11-26 17:14 org/apache/poi/ss/usermodel/
2970 2012-11-26 17:14 org/apache/poi/ss/usermodel/WorkbookFactory.class