django-rest-framework custom viewset retrive with multiple l

Question

我有两个模型，分别说A和B。

模型看起来像

class A(models.Model):
name = models.CharField(max_length=100)
description = models.CharField(max_length=1000)
slug = models.CharField(max_length=100)
class B(models.Model):
name = models.CharField(max_length=100)
description = models.CharField(max_length=1000)
slug = models.CharField(max_length=100)
A = models.foreignkey(A, models.SET_NULL, blank=true)

序列化程序

Class ASerializer(serializers.HyperlinkedModelSerializer):
class Meta:
model = A
fields = '__all__'
lookup_field = 'slug'
extra_kwargs = {'url': {'lookup_field': 'slug'}}

Class BSerializer(serializers.ModelSerializer):
class Meta:
model = B
fields = '__all__'

模型视图集

from rest_framework import viewsets, permissions
from rest_framework.response import Response
from rest_framework.decorators import action
from .models import (A, B)
from .serializers import (ASerializer, BSerializer)

Class AViewSet(viewsets.ModelViewSet):
queryset = A.objects.all()
serializer_class = ASerializer
permission_classes =                           (permissions.DjangoModelPermissionsOrAnonReadOnly, )
lookup_field = 'slug'
def retrieve(self, request, *args, **kwargs):
instance = self.get_object()
bs = B.objects.filter(A=instance.id)
serializer = BSerializer(bs, many=True)
return Response(serializer.data)

我想访问类似 url 的内容

Url: ^A/<slug>/B/slug>/$

我浏览了 Django Restframework 文档，发现我们可以添加自定义网址，例如 ( drf-custom-rounting.我不明白如何制作上面的访问 url 模式。

如何像这样定制？

编辑：我已经解决了我的问题。我在这里找到了类似类型的问题解决方案。感谢您的所有回复。

Answer 1

我认为您正在寻找一种制作嵌套网址的方法。

DRF文档的推荐方式正在使用这个包：https://github.com/alanjds/drf-nested-routers

使用示例：

首先创建视图集：

Class BViewSet(viewsets.ModelViewSet):
queryset = B.objects.all()
serializer_class = BSerializer
lookup_field = 'slug'
def retrieve(self, request, a_slug=None, b_slug=None):
a = self.get_object()
# Now you retrieve all B related to A
bs = B.objects.filter(A=a)
serializer = BSerializer(bs, many=True)
return Response(serializer.data)

然后，使用 drf 嵌套路由器注册视图集：

from rest_framework_nested import routers
from .viewsets import AViewSet, BViewSet
a_router = routers.SimpleRouter()
a_router.register(r'A', AViewSet)
b_router = routers.NestedSimpleRouter(a_router, r'B')
b_router.register(r'B', BViewSet)
urlpatterns = patterns('',
url(r'^', include(a_router.urls)),
url(r'^', include(b_router.urls)),
)

Answer 2

在你的 urls.py

from django.conf.urls import url, include
from rest_framework import routers
router = routers.DefaultRouter()
router.register(r'yourregex', views.AViewSet)
urlpatterns = [
url(r'^api/', include(router.urls)),
]