Android HttpPost请求超时

Question

在我的应用程序中，我必须从4个不同的url中获取数据，然后在完成获取数据后，我必须以特定的顺序显示项目。我正在使用HttoPost发送邮件请求。我在不同的线程中发送4个请求。当线程获取数据时，它会增加一个计数。当计数达到4时，意味着所有4个线程都已获取数据。问题是，有时四个线程中有一个没有响应，这意味着defaultHttpClient.execute（post）不会返回。因此，我的计数并没有达到4，即使它没有抛出异常，只显示等待对话框。我希望在固定的时间后，无论是否从服务器得到响应，它都必须返回。知道吗？

Answer 1

它不起作用。我正在使用以下类：

public class ConnectionManager {
private  ArrayList <NameValuePair> params;
private  ArrayList <NameValuePair> headers;
private String url;
public ConnectionManager(String url) {
    this.url = url;
    params = new ArrayList<NameValuePair>();
    headers = new ArrayList<NameValuePair>();
}
public void addParam(String name, String value)
{
    params.add(new BasicNameValuePair(name, value));
}
public void addHeader(String name, String value)
{
    headers.add(new BasicNameValuePair(name, value));
}
public String sendRequest() throws Exception {
    String serverResponse = "";
    HttpPost httpPostRequest = new HttpPost(url);
    httpPostRequest.getParams().setParameter(CoreProtocolPNames.USE_EXPECT_CONTINUE, Boolean.FALSE);
    //add headers
    for(int i = 0; i < headers.size(); i++) {
        StringEntity entity = new StringEntity(headers.get(i).getValue(),"UTF-8");
        httpPostRequest.setEntity(entity);
    }
    if(!params.isEmpty()){
        HttpEntity httpEntity = new UrlEncodedFormEntity(params,HTTP.UTF_8);
        httpPostRequest.setEntity(httpEntity);
    }
    serverResponse = executeRequest(httpPostRequest);
    return serverResponse;
}
private String executeRequest(HttpUriRequest request) throws Exception  {
    HttpParams params = new BasicHttpParams();
    HttpConnectionParams.setConnectionTimeout(params, 3000);
    HttpConnectionParams.setSoTimeout(params, 10000);
    DefaultHttpClient client = new DefaultHttpClient(params);
    HttpResponse httpResponse;
    String serverResponse = "";
    httpResponse = client.execute(request);
    HttpEntity entity = httpResponse.getEntity();
    if (entity != null) {
        InputStream instream = entity.getContent();
        serverResponse = convertStreamToString(instream);
        instream.close();
    }
    Log.d("server response", serverResponse);
    return serverResponse;
}
private String convertStreamToString(InputStream is) {
    BufferedReader reader = new BufferedReader(new InputStreamReader(is));
    StringBuilder sb = new StringBuilder();
    String line = null;
    try {
        while ((line = reader.readLine()) != null) {
            sb.append(line + "n");
        }
    } catch (IOException e) {
        e.printStackTrace();
    } finally {
        try {
            is.close();
        } catch (IOException e) {
            e.printStackTrace();
        }
    }
    return sb.toString();
}