我有以下查询:
-- CTE to remove outliers, e.g. remove the fastest and slowest results
;WITH MinMaxCTE AS
(
SELECT ServerName, CONVERT(VARCHAR(10), UpdatedOn, 101) AS [Date], Version,
MIN(JaguarStartupTime) AS MinStartTime, MAX(JaguarStartupTime) AS MaxStartTime
FROM dbo.MachineConfiguration (NOLOCK)
WHERE DomainLogin NOT IN (SELECT DomainLogin FROM dbo.SupportGroup)
GROUP BY ServerName, CONVERT(VARCHAR(10), UpdatedOn, 101), Version
)
SELECT AVG(mc.JaguarStartupTime) AS AverageTime
, COUNT(*) AS NumEntries
, mc.Version
FROM #Eligible mc (NOLOCK)
JOIN MinMaxCTE cte ON mc.ServerName = cte.ServerName
AND CONVERT(VARCHAR(10), mc.UpdatedOn, 101) = cte.[Date]
AND mc.Version = cte.Version
AND mc.JaguarStartupTime <> cte.MinStartTime
AND mc.JaguarStartupTime <> cte.MaxStartTime
GROUP BY mc.Version
ORDER BY Version DESC, AVG(mc.JaguarStartupTime) ASC
#Cile Temp表的定义是
create table #Eligible (
Version nvarchar(50), JaguarStartupTime int,
ServerName nvarchar(50), UpdatedOn datetime )
无论我评论哪种条件或聚合,我总是会收到以下错误: Arithmetic overflow error converting expression to data type int
。
我可以从这里去哪里?我该如何进一步调试?
编辑:示例数据
Version JaguarStartupTime ServerName UpdatedOn
6.4.6.082 16040 NewOrleansLA 2012-08-08 12:34:12.330
6.5.1.012 40390 BatonRougeLA 2012-08-08 18:33:17.440
6.5.1.012 48379 HonoluluHI 2012-08-09 04:42:50.453
您是否尝试过将jaguarstartup时间施放到avg汇总的bigint时,例如...
avg(cast(Mc.Jaguarstartiptime as Bigint))
这应该整理出算术溢出。
要计算服务器需要首先总和所有ints的平均值,因此,即使返回的答案在int