Bash:如果所有条件都为真，则在多个条件下匹配

Question

我正在编写一个脚本，用于检查 3 个不同的变量并在 true 上匹配。但是，我只需要它仅在所有条件匹配时才返回 true。现在，如果我的运算符列表中只有一个或两个条件匹配，则返回 true。

if [ -z "$VAR3" ] || [ "$VAR1" -ge 10 ] || [ "$VAR2" != "WORKING" ]; then
    echo "app failed "$VAR1" check-ins"
    exit 2
elif [ -n "$VAR3" ] || [ "$VAR1" -le 10 ] || [ "$VAR2" == "WORKING" ]; then
    echo "$VAR3" pid active connection is "$VAR2"
    exit 0
fi

我应该只用 &&&？？

Answer 1

是的

，||表示OR逻辑运算符，如果至少有一个运算符true，它将返回true。 &&表示AND逻辑运算符，则返回当且仅当所有运算符都true true

if [ -z "$VAR3" ] && [ "$VAR1" -ge 10 ] && [ "$VAR2" != "WORKING" ]; then
    echo "app failed "$VAR1" check-ins"
    exit 2
elif [ -n "$VAR3" ] && [ "$VAR1" -le 10 ] && [ "$VAR2" == "WORKING" ];    then
    echo "$VAR3" pid active connection is "$VAR2"
    exit 0
fi