Python，写一个非常基本的闹钟

Question

我刚刚用python写了一个非常基本的闹钟，当下午2点15分有食物煮好时，它会警告我，但是我在某个地方读到过那个时间。当其他程序正在处理时，睡眠会浪费时间，我应该用什么来代替?我现在的代码，非常基本-

import time
import winsound
time.sleep(370800)
winsound.Beep(1000,10000)

Answer 1

定期检查。下面的代码应该没问题。您可以根据需要调整timeout变量:

timeout = 10
target = time.time() + 370800
while True:
    diff = target - time.time()
    if diff < timeout:
        if diff > 0:  # highly unlikely that diff will go below 0 but just in case
            time.sleep(diff)
        break
    else:
        time.sleep(timeout)
winsound.Beep(1000,10000)