我正在开发我的新iPhone应用程序,因为我需要来自一个URL的数据和地址,我需要从另一个url获取图像。这两个结果采用 json 响应数据的形式,但我只得到数据的结果......
这是我的代码
- (void)viewDidLoad
{
jsondataimg=[[NSMutableString alloc] initWithString:@""];
#####for this url i'm not getting the result##########
NSString *urlimg = [NSString stringWithFormat:@"https://ajax.googleapis.com/ajax/services/search/images?v=1.0&q=%@",name];
//NSLog(@"%@",urlimg);
NSURL *url1= [NSURL URLWithString:urlimg];
NSURLRequest *request1 = [[NSURLRequest alloc] initWithURL: url1];
NSURLConnection *connection1 = [[NSURLConnection alloc] initWithRequest:request1 delegate:self];
jsonData = [[NSMutableString alloc] initWithString:@""];
NSString *urlString = [NSString stringWithFormat: @"https://maps.googleapis.com/maps/api/place/details/json?reference=%@&sensor=false&key=your key",selectedname];
NSLog(@" the name is%@",selectedname);
NSLog(@" the reference is%@",selectedrefer);
NSURL *url = [NSURL URLWithString:urlString];
NSURLRequest *request = [[NSURLRequest alloc] initWithURL: url];
NSURLConnection *connection = [[NSURLConnection alloc] initWithRequest:request delegate:self];
[connection release];
[request release];
[connection1 release];
[request1 release];
[super viewDidLoad];
}
- (void)connection:(NSURLConnection *)connection didReceiveData:(NSData *)data
{
NSString *partialData = [[NSString alloc] initWithData:data encoding:NSUTF8StringEncoding];
NSString *partialData1 = [[NSString alloc] initWithData:data encoding:NSUTF8StringEncoding];
[jsondataimg appendString:partialData1];
[jsonData appendString:partialData];
[partialData release];
[partialData1 release];
}
- (void)connectionDidFinishLoading:(NSURLConnection *)connection
{
# pragma mark for fetching the image urls
NSDictionary *imageurls=[jsondataimg JSONValue];
NSDictionary*images=[imageurls objectForKey:@"responseData"];
NSLog(@"%@",images);
##########here null value is displaying#######
#pragma mark for fetching the datassss
NSDictionary *filesJSON = [jsonData JSONValue];
NSDictionary *address1 = [filesJSON valueForKey:@"result"];
NSLog(@"Found %@",address1);
}
只需使用它,无需设置委托方法 nsurl 连接.. 你会得到数据...下一个也一样。
NSURLRequest *request = [NSURLRequest requestWithURL:[NSURL URLWithString:[NSString stringWithFormat:@"https://ajax.googleapis.com/ajax/services/search/images?v=1.0&q=mumbai"]]];
NSURLResponse *response;
NSError *error;
NSData *responseData = [NSURLConnection sendSynchronousRequest:request returningResponse:&response error:&error];
NSString *strResponse = [[NSString alloc] initWithData:responseData encoding:NSUTF8StringEncoding];
// NSLog(@"%@",strResponse);
SBJSON *sbJason = [[SBJSON alloc] init];
NSMutableDictionary *getPlaceList = [sbJason objectWithString:strResponse];