我有一个生成字符串的Enumerator::Generator
实例。我需要把它们连成一根绳子。
做这件事的好方法是什么?我注意到*
不起作用。我知道我可以先.map {|x| x}
,但这似乎不太习惯
我认为在这种情况下,我可能会使用+
运算符来获取inject
/reduce
(同一方法的别名,reduce
作为名称对我来说更有意义(
enum.reduce(:+)
# or, passing in a block
enum.reduce(&:+)
举个完整的例子:
# never used Enumerator::Generator directly, but you called it out specifically
# in your question, and this seems to be doing the trick to get it working
enum = Enumerator::Generator.new do |y|
y.yield "ant"
y.yield "bear"
y.yield "cat"
end
p enum.reduce(&:+) # output: "antbearcat"
# crude example of modifying the strings as you join them
p enum.reduce('') { |memo, word| memo += word.upcase + ' ' }
# output: "ANT BEAR CAT "
a=["Raja","gopalan"].to_enum #let's assume this is your enumerator
编写以下代码
p a.map(&:itself).join
或
p a.to_a.join
输出
"Rajagopalan"