d=[[5,3,2],[5,1,9],[6,8,3]]
我需要将此嵌套列表除以"2">
我尝试过的代码。
m=[]
jj=2for k,v in zip(d,jj):
m.append([k2/v2 for k2,v2 in zip(k,v)])
print(m)
所以输出可能如下所示
d=[[2.5,1.5,1],[2.5,0.5,4.5],[3,4,1.5]
d=[[5,3,2],[5,1,9],[6,8,3]]
result = [[j/2 for j in i] for i in d]
print(result)