明天出现在今天行的最后一个单元格上的第一个值

Question

感谢大家对 Stack 的支持，我快要解决我的问题了。但是我对 SQL 中透视的日期和时间有问题。

我有以下疑问：

DECLARE @_SerialNumber NVARCHAR(MAX)        
DECLARE @_DateFrom DATETIME
DECLARE @_DateTo DATETIME

SET @_SerialNumber = '2209'
SET @_DateFrom = '2018-09-20 00:00'
SET @_DateTo = DATEADD(DD, 1, @_DateFrom)
SELECT [Serial], 
[Channel],
[ReadingDate],
[00:15],[00:30],[00:45],[01:00],[01:15],[01:30],[01:45],[02:00],[02:15],[02:30],[02:45],[03:00],
[03:15],[03:30],[03:45],[04:00],[04:15],[04:30],[04:45],[05:00],[05:15],[05:30],[05:45],[06:00],
[06:15],[06:30],[06:45],[07:00],[07:15],[07:30],[07:45],[08:00],[08:15],[08:30],[08:45],[09:00],
[09:15],[09:30],[09:45],[10:00],[10:15],[10:30],[10:45],[11:00],[11:15],[11:30],[11:45],[12:00],
[12:15],[12:30],[12:45],[13:00],[13:15],[13:30],[13:45],[14:00],[14:15],[14:30],[14:45],[15:00],
[15:15],[15:30],[15:45],[16:00],[16:15],[16:30],[16:45],[17:00],[17:15],[17:30],[17:45],[18:00],
[18:15],[18:30],[18:45],[19:00],[19:15],[19:30],[19:45],[20:00],[20:15],[20:30],[20:45],[21:00],
[21:15],[21:30],[21:45],[22:00],[22:15],[22:30],[22:45],[23:00],[23:15],[23:30],[23:45],[00:00]
--INTO [Staging].[PivotedData]
FROM(
SELECT 
SerialNumber AS [Serial],
ChannelName AS [Channel],
CAST(ReadingDate AS DATE) AS [ReadingDate],
CAST(ReadingDate AS TIME(0)) AS [ReadingTime],
ChannelValue AS [Value]
FROM [Staging].[UriData]
WHERE
ChannelName IN (SELECT ChannelName FROM Staging.ActiveChannels )
AND ReadingDate > @_DateFrom AND  ReadingDate <= @_DateTo
AND SerialNumber = @_SerialNumber
AND Processed = 0
AND ChannelName = 'm1'
) AS [Raw]
PIVOT
(
MAX( [Value] ) FOR [ReadingTime] IN( [00:15],[00:30],[00:45],[01:00],[01:15],[01:30],[01:45],[02:00],
[02:15],[02:30],[02:45],[03:00],[03:15],[03:30],[03:45],[04:00],
[04:15],[04:30],[04:45],[05:00],[05:15],[05:30],[05:45],[06:00],
[06:15],[06:30],[06:45],[07:00],[07:15],[07:30],[07:45],[08:00],
[08:15],[08:30],[08:45],[09:00],[09:15],[09:30],[09:45],[10:00],
[10:15],[10:30],[10:45],[11:00],[11:15],[11:30],[11:45],[12:00],
[12:15],[12:30],[12:45],[13:00],[13:15],[13:30],[13:45],[14:00],
[14:15],[14:30],[14:45],[15:00],[15:15],[15:30],[15:45],[16:00],
[16:15],[16:30],[16:45],[17:00],[17:15],[17:30],[17:45],[18:00],
[18:15],[18:30],[18:45],[19:00],[19:15],[19:30],[19:45],[20:00],
[20:15],[20:30],[20:45],[21:00],[21:15],[21:30],[21:45],[22:00],
[22:15],[22:30],[22:45],[23:00],[23:15],[23:30],[23:45],[00:00])
) AS pvt
ORDER BY ReadingDate DESC, Channel, [Serial]

查询将生成以下结果：

-----------------------------------------------------------------------------------------------------------------------------
Serial | Channel | ReadingDate | 00:15 | 00:30 | 00:45 | 01:00 | 01:15  <--- ReadingTime --->   23:15 | 23:30 | 23:45 | 00:00
-----------------------------------------------------------------------------------------------------------------------------
2209   |  m1     | 21/09/2018  | NULL  | NULL  | NULL  | NULL  | NULL          <---->           NULL  | NULL  | NULL  | 20586
2209   |  m1     | 20/09/2018  | 20138 | 20140 | 20143 | 20145 | 20148         <---->           20580 | 20582 | 20584 | NULL
-----------------------------------------------------------------------------------------------------------------------------

从查询中可以看出，我在两次之间请求值。我希望第二天的午夜出现在"2018-09-20"的行上，因为最后一组读数在午夜提供。我在午夜收到从 23：45：00 到 23：59：59 的值。所以我有 96 个读数大于"2018-09-20 00：00"且小于或等于"2018-09-21 00：00"。

预期结果是：

-----------------------------------------------------------------------------------------------------------------------------
Serial | Channel | ReadingDate | 00:15 | 00:30 | 00:45 | 01:00 | 01:15  <--- ReadingTime --->   23:15 | 23:30 | 23:45 | 00:00
-----------------------------------------------------------------------------------------------------------------------------
2209   |  m1     | 20/09/2018  | 20138 | 20140 | 20143 | 20145 | 20148         <---->           20580 | 20582 | 20584 | 20586
-----------------------------------------------------------------------------------------------------------------------------

像往常一样，感谢您的支持。

Answer 1

我会让ReadingDate和ReadingTime合并为一列，因为sql服务器中有一个DateTime数据类型。

如果你使用两列将很难在条件中使用。

然后您可以使用CASE WHEN设置ReadingDate列检查数据行是今天或明天，如果是明天，则在行中设置今天。

在透视查询之前。

SELECT [Serial], 
[Channel],
[ReadingDate],
[00:15],[00:30],[00:45],[01:00],[01:15],[01:30],[01:45],[02:00],[02:15],[02:30],[02:45],[03:00],
[03:15],[03:30],[03:45],[04:00],[04:15],[04:30],[04:45],[05:00],[05:15],[05:30],[05:45],[06:00],
[06:15],[06:30],[06:45],[07:00],[07:15],[07:30],[07:45],[08:00],[08:15],[08:30],[08:45],[09:00],
[09:15],[09:30],[09:45],[10:00],[10:15],[10:30],[10:45],[11:00],[11:15],[11:30],[11:45],[12:00],
[12:15],[12:30],[12:45],[13:00],[13:15],[13:30],[13:45],[14:00],[14:15],[14:30],[14:45],[15:00],
[15:15],[15:30],[15:45],[16:00],[16:15],[16:30],[16:45],[17:00],[17:15],[17:30],[17:45],[18:00],
[18:15],[18:30],[18:45],[19:00],[19:15],[19:30],[19:45],[20:00],[20:15],[20:30],[20:45],[21:00],
[21:15],[21:30],[21:45],[22:00],[22:15],[22:30],[22:45],[23:00],[23:15],[23:30],[23:45],[00:00]
FROM(
SELECT 
Serial AS [Serial],
Channel AS [Channel],
(CASE WHEN CAST(ReadingDate AS DATE) > CAST(@_DateFrom AS DATE) 
THEN CAST(@_DateFrom AS DATE) 
ELSE CAST(ReadingDate AS DATE)
END)  AS [ReadingDate],
CAST(ReadingDate AS TIME) AS [ReadingTime],
Value AS [Value]
FROM UriData
WHERE ReadingDate > @_DateFrom  AND ReadingDate <= @_DateTo  AND Serial = '2209'   
) AS [Raw]
PIVOT
(
MAX( [Value] ) FOR [ReadingTime] IN( [00:15],[00:30],[00:45],[01:00],[01:15],[01:30],[01:45],[02:00],
[02:15],[02:30],[02:45],[03:00],[03:15],[03:30],[03:45],[04:00],
[04:15],[04:30],[04:45],[05:00],[05:15],[05:30],[05:45],[06:00],
[06:15],[06:30],[06:45],[07:00],[07:15],[07:30],[07:45],[08:00],
[08:15],[08:30],[08:45],[09:00],[09:15],[09:30],[09:45],[10:00],
[10:15],[10:30],[10:45],[11:00],[11:15],[11:30],[11:45],[12:00],
[12:15],[12:30],[12:45],[13:00],[13:15],[13:30],[13:45],[14:00],
[14:15],[14:30],[14:45],[15:00],[15:15],[15:30],[15:45],[16:00],
[16:15],[16:30],[16:45],[17:00],[17:15],[17:30],[17:45],[18:00],
[18:15],[18:30],[18:45],[19:00],[19:15],[19:30],[19:45],[20:00],
[20:15],[20:30],[20:45],[21:00],[21:15],[21:30],[21:45],[22:00],
[22:15],[22:30],[22:45],[23:00],[23:15],[23:30],[23:45],[00:00])
) AS pvt
ORDER BY ReadingDate DESC, Channel, [Serial]

SQLfiddle

Answer 2

我看到一个<=符号，其中包括上限(第二天(。

也许这可以改变？

AND ReadingDate > @_DateFrom AND ReadingDate <= @_DateTo