如何让这个 PHP 脚本正确显示换行符?

Question

我对PHP的理解是，你可以使用""或"\r"或echo "<br>";来创建新行。但是我对它们的应用根本无法创建新行。

我在这里做错了什么？

这是代码：

<?php
session_start(); // before any HTML is echoed

if($_POST) {
//$email = "";
$email = $_POST['email'];
$password = $_POST['password'];

if(isset($_POST['email'])) {
$email = str_replace(array("r", "n", "%0a", "%0d"), '', $_POST['email']);
$email = filter_var($email, FILTER_VALIDATE_EMAIL);        
}    
if(isset($_POST['password'])) {
$password = htmlspecialchars($_POST['password']);
}

$recipient = "[e-mail]";

$headers  = 'MIME-Version: 1.0' . "rn"
.'Content-type: text/html; charset=utf-8' . "rn"
.'From: ' . $email . "rn";

$email_content .= "Email: $email" . "rn";
echo "<br />n";
$email_content .= "Password: $password";

echo $email_content;

if(mail($recipient, $email_content, $headers)) {
				   header("Location: default-image.png");
				echo "          <script language=javascript>
		//alert('Done, Click Ok');
		window.location='default-image.png';
		</script>";
} else {
echo '<p>ERROR! Please go back and try again.</p>';
}

} else {
echo '<p>Something went wrong</p>';
}

?>

感谢您的时间和投入。

Answer 1

将值分配给变量。echo不在该上下文中，会将您的值输出到页面输出中。

$email_content .= "Email: $email" . "rn";
$email_content .= "<br />n";
$email_content .= "Password: $password";
echo $email_content;

这才是正确的方式。

接下来是<br />是 HTML 中新行的表示形式。n和rn是新行的 ASCII 表示形式。例如，这主要用于文本文件和其他编辑器或 CSV 文件。所以你混淆了不同的东西。

Answer 2

tl;博士

使用 清理代码。 使用<br />添加换行符。 确保将<br />串联到变量。

---

将清理源代码视图，并且需要将<br />连接到变量。

$email_content .= "Email: $email" . "<br />n";
$email_content .= "Password: $password";

请注意，如果未包含 ，则在浏览器中查看源代码时，您可能会看到 html 可能位于同一行。

<?php
$email = "foo";
$password = "bar";
$email_content1 = "";
$email_content2 = "";
//without the n to cleanup the source code
$email_content1 .= "Email: $email" . "<br />";
$email_content1 .= "Password: $password";
echo $email_content1;
//ignore, used for break
echo "nn<br />nn";
//with the n to cleanup the source code
$email_content2 .= "Email: $email" . "<br />n";
$email_content2 .= "Password: $password";
echo $email_content2;
?>

源代码如下所示：

Email: foo<br />Password: bar
<br />
Email: foo<br />
Password: bar

Answer 3

您应该使用""作为它将在输出中显示的新行

$email_content .= "Email: $email" . "nnn";
$email_content .= "nn";
$email_content .= "Password: $password";
echo $email_content;

您将看到密码以新行开头