我有数据帧df
:
id timestamp data group_id date
56729 56970 2020-02-01 01:22:52.717 21.0 1 2020-02-01
57135 57376 2020-02-01 14:11:22.633 38.0 3 2020-02-01
57136 57377 2020-02-01 14:11:22.733 39.0 3 2020-02-01
57137 57378 2020-02-01 14:11:23.637 39.0 3 2020-02-01
57138 57379 2020-02-01 14:11:23.737 40.0 3 2020-02-01
和代码:
df = df[df['data'] >0]
df['timestamp'] = pd.to_datetime(df['timestamp'])
start_date = pd.to_datetime('2020-02-01 00:00:00')
end_date = pd.to_datetime('2020-03-01 00:00:00')
df = df.loc[(df['timestamp'] > start_date) & (df['timestamp'] < end_date)]
df['date'] = df['timestamp'].dt.date
df = df.sort_values(by=['date'])
df = df[df['date'] == '2020-02-01']
列date
是在datetime
的基础上创建的,这样我以后就可以用date
对df
进行分组。但当我在某个日期(比如2020-02-01
(对df
进行切片时,代码什么都没有返回,因为那里有当天的数据。输出看起来是这样的:
id timestamp data group_id date
这只是列名称。怎么了?
您的df[date]
列包含类似datetime
的值,而不是string
,因此这些值将不等于'2020-02-01'
,您可以执行以下操作之一:
>>> df[df['date'] == pd.to_datetime('2020-02-01')]
或者,
>>> df[df['date'].astype(str) == '2020-02-01']
您的df['date']
日期对象类型数据,同时将其与第df = df[df['date'] == '2020-02-01']
行的字符串进行比较。看看下面的解决方案:
import pandas as pd
dic = {'timestamp': ['2020-02-01 01:22:52.717', '2020-02-01 01:24:52.717', '2020-02-02 01:22:52.717',
'2020-02-03 01:22:52.717']}
df = pd.DataFrame(dic)
df['timestamp'] = pd.to_datetime(df['timestamp'])
print(df['timestamp'])
start_date = pd.to_datetime('2020-02-01 00:00:00')
end_date = pd.to_datetime('2020-03-01 00:00:00')
df = df.loc[(df['timestamp'] > start_date) & (df['timestamp'] < end_date)]
df['date'] = df['timestamp'].dt.date
print(df['date'])
df = df.sort_values(by=['date'])
df = df[df['date'] == pd.to_datetime('2020-02-01')]
print(df)
输出:
0 2020-02-01 01:22:52.717
1 2020-02-01 01:24:52.717
2 2020-02-02 01:22:52.717
3 2020-02-03 01:22:52.717
Name: timestamp, dtype: datetime64[ns]
0 2020-02-01
1 2020-02-01
2 2020-02-02
3 2020-02-03
Name: date, dtype: object
timestamp date
0 2020-02-01 01:22:52.717 2020-02-01
1 2020-02-01 01:24:52.717 2020-02-01