我有一个表Products
,我需要在其上创建触发器来更新另一个表中数据的更改(新数据(Products_audit
,该表具有相同列和相同数据。
我尝试过以下内容:
CREATE TRIGGER Super
ON Products
AFTER INSERT, UPDATE
AS
UPDATE Product_audit (Column1,Column2, Column3, ... )
SELECT (Column1,Column2,Column3,...)
FROM Products
收到以下错误:
Server: Msg 170, Level 15, State 31, Procedure Super, Line 20
Line 20: Incorrect syntax near '('.
Server: Msg 170, Level 15, State 1, Procedure Super, Line 24
Line 24: Incorrect syntax near ','.
我使用sql server 2000
我在触发器创建方面不是很强,你能纠正我吗?我想知道我错在哪里了?
我认为您的触发器需要看起来像这样:
CREATE TRIGGER Super
ON Products
AFTER INSERT, UPDATE
AS
UPDATE Product_audit
SET Column1 = p.Column1
SET Column2 = p.Column2
FROM Products p
你好,您必须创建两个不同的触发器,一个用于更新,另一个用于插入1( 用于插入
CREATE TRIGGER Super
ON Products
AFTER INSERT
AS
BEGIN
INSERT INTO Product_audit
(Column1,Column2,...)
SELECT Column1,Column2,...
FROM Inserted
END
2( 用于更新
CREATE TRIGGER Super
ON Products
AFTER Update
AS
BEGIN
DECLARE @Column1 as varchar(10)
DECLARE @Column2 as varchar(10)
DECLARE @ID INT
SELECT @ID=ID,@Column1=Column1,@Column2=Column2 FROM INSERTED
UPDATE Product_audit SET Column1=@Column1,Column2=@Column2
WHERE ID=@ID
END