Gulp：对象 #<File> 没有方法'isNull'

Question

我从gulp-concat和gulp-sass那里得到了TypeError: Object #<File> has no method 'isNull'：

gulp.task('scripts', function() {
    var dest = BUILD_DEST + 'scripts';
    del(dest);
    return gulp
        .src( scripts ) // scripts = [].concat(VENDOR_LIBS, APP_FILES)
        .pipe( plumber() )
        .pipe( concat('script.js') ) // everything is fine when this line is removed
                                     // Does the output file need to already exist?
        .pipe( gulp.dest( dest ) );
});
gulp.task('styles', function() {
    var dest = BUILD_DEST + 'styles';
    del(dest);
    return gulp
        .src( STYLE_FILES ) // STYLE_FILES = APP_SRC+'styles/*.scss'
        .pipe( plumber() )
        .pipe( sass() )
        .pipe(gulp.dest( dest ));
});

Answer 1

这是

由于不小心使用了旧版本的gulp（3.0.0 vs 3.8.10），它与gulp-concat和gulp-sass不兼容。升级到版本 3.8.10 解决了此问题。