我有这个自我关系注释
public class Estoria implements Serializable {
@EmbeddedId
protected EstoriaPK estoriaPK;
@ManyToOne
@JoinColumns({@JoinColumn(name = "id_estoria", referencedColumnName = "id", updatable = false, insertable = false, nullable = true)
,@JoinColumn(name = "id_projeto" , referencedColumnName = "id_projeto" , insertable = false, updatable = false)})
private Estoria subtask;
@OneToMany(mappedBy = "subtask",cascade = CascadeType.ALL)
private Collection<Estoria> subtasks;
}
我尝试保留此集合::
public void persistSubtasks(int idEstoria, Collection<Estoria> subtasks) {
Estoria rootEstoria = entityManager.createNamedQuery("Estoria.findById", Estoria.class)
.setParameter("id", idEstoria)
.getSingleResult();
rootEstoria.setSubtasks(subtasks);
}
但是数据库持久性没有保留根引用 ID:
+----+------------+------------+--------------------------+----------- -------------------------------------------------------------------+------ ------+--------+--------------+
| id | id_projeto | id_estoria | nome | descricao | estimativa | status | data_criacao |
+----+------------+------------+--------------------------+------------------------------------------------------------------------------+------------+--------+--------------+
| 1 | 7 | NULL | Check all old activities | No one know if every feature was checked before builded | NULL | 0 | 2015-01-02 |
| 2 | 7 | "supost to be 1" | Register all users | Everyone needs to be registered and identified by profile | NULL | 0 | 2015-01-02 |
谁能给我一些礼物?
好消息这篇文章>理解注释和 JPA(休眠)解决了我的问题,但我真的不需要参考根>>叶/叶>>根
您必须在子 ID 中设置 parrent id。在子任务集合中设置 rootEstoria id。
public void persistSubtasks(int idEstoria, Collection<Estoria> subtasks) {
Estoria rootEstoria = entityManager.createNamedQuery("Estoria.findById", Estoria.class)
.setParameter("id", idEstoria)
.getSingleResult();
for(Estoria subtask:subtasks){
subtask.setSubtask(rootEstoria);
}
rootEstoria.setSubtasks(subtasks);
}