我在虚拟机上安装了minix3,希望能够操作当前的队列选择算法,以便将其从优先级顺序更改为包括随机排列的低优先级作业的优先级顺序。我发现我需要更改的代码部分在proc.c中,具体部分是pick_proc.c。
/*===========================================================================*
* pick_proc *
*===========================================================================*/
PRIVATE struct proc * pick_proc(void)
{
/* Decide who to run now. A new process is selected and returned.
* When a billable process is selected, record it in 'bill_ptr', so that the
* clock task can tell who to bill for system time.
*/
register struct proc *rp; /* process to run */
int q; /* iterate over queues */
/* Check each of the scheduling queues for ready processes. The number of
* queues is defined in proc.h, and priorities are set in the task table.
* The lowest queue contains IDLE, which is always ready.
*/
for (q=0; q < NR_SCHED_QUEUES; q++) {
if(!(rp = rdy_head[q])) {
TRACE(VF_PICKPROC, printf("queue %d emptyn", q););
continue;
}
u64_t timecount;
u32_t randdom;
read_tsc_64(&timecount);
rand = timecount.lo;
#if DEBUG_RACE
rp = random_process(rdy_head[q]);
#endif
TRACE(VF_PICKPROC, printf("found %s / %d on queue %dn",
rp->p_name, rp->p_endpoint, q););
assert(proc_is_runnable(rp));
if (priv(rp)->s_flags & BILLABLE)
bill_ptr = rp; /* bill for system time */
return rp;
}
return NULL;
}
我已经放了一些代码来开始随机化过程,但我不知道该从哪里开始。我知道我需要向这个文件添加一些内容,但我不确定哪些变量做什么,哪些指针需要更改。我希望有人能向我展示如何做到这一点,或者指出我需要改变哪一部分来帮助我前进。现在我很困。
感觉像是一个微妙的问题;改变算法可能会导致高优先级任务无法完成。Q1:什么是"低优先级任务"?那是NR_SCHED_QUEUES/2吗?Q2:在你愿意选择优先级较低的任务之前,最多需要等待多少优先级较高的任务?回答这个问题后,您可以将for循环中的q=0更改为例如q=low_tasks,并从中选择一个进程。
for (p=0, q=0; q < NR_SCHED_QUEUES/2; q++)
p += rdy_tail[q] - rdy_head[q]; // number of processes in this queue
if (p<some_value) q= NR_SCHED_QUEUES / 2; else q= 0;
for (; q < NR_SCHED_QUEUES; q++) {
if(!(rp = rdy_head[q])) {
TRACE(VF_PICKPROC, printf("queue %d emptyn", q););
continue;
}
TRACE(VF_PICKPROC, printf("found %s / %d on queue %dn",
rp->p_name, rp->p_endpoint, q););
assert(proc_is_runnable(rp));
if (priv(rp)->s_flags & BILLABLE)
bill_ptr = rp; /* bill for system time */
return rp;
}
return NULL;
注意:这只是演示,不能保证正常工作!
注意:您还必须检查是否有优先级较低的任务要运行。