,我知道Auth::attempt
用于从users
表中验证用户,但是我想从managers
表和admins
表中的Admin验证其他用户。我知道已经存在laravel-multiauth
插件。但是,我们可以创建自己的AuthServiceProvider
,以从多个表中认证用户。?
首先在IlluminateFoundationAuth
中创建Admin Adrinable,例如
<?php
namespace IlluminateFoundationAuth;
use IlluminateAuthAuthenticatable;
use IlluminateDatabaseEloquentModel;
use IlluminateAuthPasswordsCanResetPassword;
use IlluminateFoundationAuthAccessAuthorizable;
use IlluminateContractsAuthAuthenticatable as AuthenticatableContract;
use IlluminateContractsAuthAccessAuthorizable as AuthorizableContract;
use IlluminateContractsAuthCanResetPassword as CanResetPasswordContract;
class Admin extends Model implements
AuthenticatableContract,
AuthorizableContract,
CanResetPasswordContract
{
use Authenticatable, Authorizable, CanResetPassword;
}
然后通过扩展Authenticatable
管理模型来创建管理模型: -
<?php
namespace App;
use IlluminateFoundationAuthAdmin as Authenticatable;
class Admin extends Authenticatable
{
/**
* The attributes that are mass assignable.
*
* @var array
*/
protected $fillable = [
'name', 'email', 'password',
];
/**
* The attributes that should be hidden for arrays.
*
* @var array
*/
protected $hidden = [
'password', 'remember_token',
];
}
之后您需要修改config/auth.php
如下添加提供商数组
'admins' => [
'driver' => 'eloquent',
'model' => AppAdmin::class,
],
并添加 guards 数组。
'user' => [
'driver' => 'session',
'provider' => 'users',
],
'admin' => [
'driver' => 'session',
'provider' => 'admins',
],
现在从 user 表
进行身份验证 if (Auth::guard('user')->attempt(['email' => $email, 'password' => $password])) {
$details = Auth::guard('user')->user();
$user = $details['original'];
return $user;
} else {
return 'auth fail';
}
并从 admin 表
进行身份验证 if (Auth::guard('admin')->attempt(['email' => $email, 'password' => $password])) {
$details = Auth::guard('admin')->user();
$user = $details['original'];
return $user;
} else {
return 'auth fail';
}
您可以设置多个身份验证守卫,每个人都有不同的提供商。提供者定义要使用的表或模型。
在config/auth.php
中,您设置了providers
,如下所示,还为每个提供商设置了相应的guards
:
'providers' => [
'users' => [
'driver' => 'eloquent',
'model' => AppUser::class,
],
'managers' => [
'driver' => 'eloquent',
'model' => AppManager::class,
],
'admins' => [
'driver' => 'eloquent',
'model' => AppAdmin::class,
]
]
然后您可以这样进行身份验证:
Auth::attempt($credentials) // use default guard for simple users
Auth::guard('manager')->attempt($credentials)
Auth::guard('admin')->attempt($credentials)
在此处查看文档。
如果您愿意,请尝试我的想法。我期望不同的table
具有不同的users
。因为如果您在其他表中有相同的user
,它将无法工作。
- 选择您的优先级表(例如用户)
- 添加条件
-
if(Auth::user(attempt(...))
-
elseif(Auth::manager(attempt(...))
-
elseif(Auth::admins(attempt(...)))
-
注意:您的优先表是users
,则如果用户不存在该表中的用户,它将尝试managers
表,如果仍然不存在,则将检查admins
表,否则(使用else
)返回消息错误。
其他选项:
其他选项是使用此软件包sarav/laravel-multiauth
。您可以关注此线程。如何将身份验证用于Laravel 5中的多个表格以获取更多信息。
更多参考:
https://laracasts.com/discuss/channels/general-discussion/using-laravel-auth-auth-for-multiple-tables?page = 1
任何人都可以解释Laravel 5.2多验证示例
https://laracasts.com/discuss/channels/laravel/52-auth-multiple-tables?page=1
为管理者表和管理表创建模型。该模型应扩展IlluminateFoundationAuthUser
在config/auth.php
中,
添加到提供商数组:
'managers' => [
'driver' => 'eloquent',
'model' => AppManager::class,
],
添加到守卫阵列:
'web_manager' => [
'driver' => 'session',
'provider' => 'managers',
],
然后。在LoginController
(使用php artisan make:auth
创建一个用于管理器的创建)中,请使用特质IlluminateFoundationAuthAuthenticatesUsers
和覆盖后卫和重定向属性。
protected $redirectTo = 'redirect_path_after_manager_login';
protected function guard()
{
return Auth::guard('web_manager');
}
管理器模型已进行身份验证,您可以获取Auuthenticatienatienationed Manager的对象Auth::guard('web_manager')->user();