使测试脚本与时区无关

Question

我有一个脚本(Java(，它向不同时区的组件发送订单：

final Date now = new Date();
long effectiveTime = now.getTime();
long expireTime = DateUtils.addMinutes(now, 2).getTime();
order.setEffectiveTime(effectiveTime)
     .setExpireTime(expireTime)
     .send();

现在，由于我在 GMT+1 并且组件是 GMT-0(伦敦(，因此我按如下方式验证：

// Shift 1 hour
SimpleDateFormat f = new SimpleDateFormat("HH:mm:ss");
final String expectedEffectiveTime =  f.format(DateUtils.addHours(now,-1));
final String expectedExpireTime = f.format(DateUtils.addHours(DateUtils.addMinutes(now, 2),-1));
String logString = getLogString(order);
Assert.assertTrue(logString.contains(expectedEffectiveTimeText));
Assert.assertTrue(logString.contains(expectedExpireTimeText));

上述方法有效，但前提是您在我的时区运行脚本。当然，在任何其他时区运行脚本都会失败。有没有一种优雅的方法以与时区无关的方式编写脚本，唯一不变的是预期输出将调整为 GMT-0？

Answer 1

感谢Andy Turner的评论，我找到了使用Java 8的解决方案：

ZonedDateTime now = ZonedDateTime.ofInstant(Instant.now(),ZoneId.systemDefault()); 
// need longs because setter methods accept either Date or long 
long effectiveTime = now.toInstant().toEpochMilli();
long expireTime = now.plusMinutes(2).toInstant().toEpochMilli();

// send 
order.setEffectiveTime(effectiveTime)
      .setExpireTime(expireTime)
      .send();

// Verify
String expectedEffectiveTime = now.withZoneSameInstant(ZoneId.of("Europe/London"))
                                  .toLocalTime().toString();
String expectedExpireTime = now.withZoneSameInstant(ZoneId.of("Europe/London"))
                               .plusMinutes(2).toLocalTime().toString();

String logString = getLogString(order);
Assert.assertTrue(logString.contains(expectedEffectiveTimeText));
Assert.assertTrue(logString.contains(expectedExpireTimeText));