我如何使代码跳到if语句中的某个点

Question

我正在做一个基本的游戏。我想知道如何使代码转到代码/if语句中的特定点，而不是从头开始。

例如，在我的代码第 19 行中：kithcen()我不想将其重定向到 if 语句的开头; 再次继续描述厨房，然后要求输入：choice02 = raw_input("What do you do?")，但我希望它直接跳到输入部分。

def kitchen():
print "You see a dusty old kitchen, nobody has probably used it for quite a while."
print "There are 3 different cupboards(0, 1, 2) or a letter(3) placed on the counter."
choice02 = raw_input("What do you do? >")
if choice02 == "0" or choice02 == "first cupboard" or choice02 == "check first cupboard" or choice02 == "open first cupboard":
print "You see a dusty empty bottles of milks, with spiderwebs at the corners of the cupboard. Nothing of Interest here."
raw_input(">")
kitchen()
elif choice02 == "1" or choice02 == "second cupbaord" or choice02 == "check second cupboard" or choice02 == "open second cupboard":
print "You see some packs of likely expired cereal and a key(0)."
choice_02_A = raw_input("What do you do? >")
#----------------------------------------------------------------------------------------------------------#
if choice02_A == "pick key" or choice02_A == "key" or choice02_A == "0" or choice02_A == "get key":
print "You picked the key. This probably unlocks some door."
raw_input("> ")
kitchen()
elif choice02_A == "close cupboard" or choice02_A == "kitchen" or choice02_A == "go back to kitchen":
kitchen()
else:
print "Not a valid option."
#-----------------------------------------------------------------------------------------------------------#
elif choice02 == "2" or choice02 == "third cupboard" or choice02 == "check third cupboard" or choice02 == "open third cupboard":
print "You see an empty or dusty cupboard. Nothing of interest here."
raw_input("> ")
kitchen()
elif choice02 == "3" or choice02 == "check letter" or choice02 == "letter" or choice02 == "read letter":
print """
You read the letter:
n"Dear Shawn............n"
It makes no sense to you.
"""

elif choice02 == "go back" or choice02 == "entrance hall" or choice02 == "go to entrance hall":
entrance_hall()
else:
"Not a valid Option."

Answer 1

我没有看到循环，但是如果您只想要从外部调用函数时的 print 语句，则可以使用如下所示的可选布尔值：

def kitchen(already_there=False):
if not already_there:
print('...')
choice02 = raw_input("What do you do? >")
# ...
elif # ...
# ...
kitchen(already_there=True)

Answer 2

您可能需要考虑重构代码并使用字典来避免冗长的 if-else 语句。

请参阅 https://stackoverflow.com/a/27365077/2884613。

print "There are 3 different cupboards(0, 1, 2) or a letter(3) placed on the counter." 
alias = {
'0': '0',
'first cupboard': '0',
'check first cupboard': '0',
'open first cupboard': '0',
'1': '1',
'second cupboard': '1',
'check second cupboard':'1',
...
}
dic = {
"0":"You see a dusty empty bottles of milks, with spiderwebs at the corners of the cupboard. Nothing of Interest here.",  
"1":"You see some packs of likely expired cereal and a key(0).",  
"2":"You see an empty or dusty cupboard. Nothing of interest here."
...
}
while(True):
choice02 = raw_input("What do you do? >")
if choice02 in alias:
print dic[alias[choice02]]
break
else:
print "Not a valid option"