我有一个看起来像这样的数据帧。它有更多的时间轴直到Time[s].30
.
Time[s] v1 Time[s].1 v2
160.84621 0 160.84808 7
161.14613 0 161.14802 7
161.538245 27 161.540085 7
162.01598 27 162.017865 7
162.31589 27 162.317775 7
162.615855 27 162.617735 7
162.915765 27 162.91765 7
163.21574 27 163.217625 7
163.51569 27 163.517575 7
163.81563 27 163.81751 7
164.11554 27 164.117425 7
164.4155 27 164.41738 9
164.71543 27 164.717315 9
165.015405 27 165.017285 9
165.31532 27 165.317205 9
165.65083 26 165.65272 9
165.95025 26 165.95214 9
我想要一个Time[s].general
时间轴,它是所有具有排序值的时间列的合并形式。我已经为所有这些列编制了索引。
df.set_index(keys=list(file_read.filter(like='Time[s]').columns))
更新:
预期产出:
Time[s] v1 v2
160.84621 0 null
160.84808 null 7
160.14613 0 null
161.14802 null 7
161.538245 27 null
161.540085 null 7
162.01598 27 null
162.017865 null 7
162.31589 27 null
162.317775 null 7
等等。
更新 2:
Time[s] v1 Time[s].1 v2 Time[s].2 v3
160.84621 0 160.84808 7 158.538395 Active
161.14613 0 161.14802 7 158.538515 Active
161.538245 27 161.540085 7 159.49455 Active
162.01598 27 162.017865 7 162.352395 Locked
162.31589 27 162.317775 7 163.35075 Locked
162.615855 27 162.617735 7 164.350675 Locked
162.915765 27 162.91765 7 165.350655 Locked
163.21574 27 163.217625 7 166.509695 Locked
163.51569 27 163.517575 7 166.509815 Locked
163.81563 27 163.81751 7 167.50086 Locked
164.11554 27 164.117425 7 168.50085 Locked
164.4155 27 164.41738 9 169.500865 Locked
164.71543 27 164.717315 9 171.502655 Standby
165.015405 27 165.017285 9 185.89923 Forward
165.31532 27 165.317205 9 3273.448065 Forward
165.65083 26 165.65272 9 3274.43487 Forward
165.95025 26 165.95214 9 3275.4348 Forward
我认为需要:
b = df.filter(like='v').columns
d = {x: 'v.{}'.format(i) for i, x in enumerate(b)}
d['Time[s]'] = 'Time[s].0'
print (d)
{'v1': 'v0', 'v2': 'v1', 'Time[s]': 'Time[s].0'}
df = df.rename(columns=d)
L = [x.set_index(x.columns[0]) for i, x in df.groupby(lambda x: x.split('.')[-1], axis=1)]
df = pd.concat(L, axis=1)
print (df.head(10))
v.0 v.1
160.846210 0.0 NaN
160.848080 NaN 7.0
161.146130 0.0 NaN
161.148020 NaN 7.0
161.538245 27.0 NaN
161.540085 NaN 7.0
162.015980 27.0 NaN
162.017865 NaN 7.0
162.315890 27.0 NaN
162.317775 NaN 7.0
消遣:
- 前
filter
列v
所有字典列,用于将时间戳与值列配对。 rename
bydict
,也是第一timestamp
列- 在列表推导式中
.
后按列的值groupby
,按set_index
和一起concat
创建索引
编辑:
如果数值和重复的时间戳聚合是按mean
,如果不是,则聚合first
:
b = df.filter(like='v').columns
d = {x: 'v.{}'.format(i) for i, x in enumerate(b)}
d['Time[s]'] = 'Time[s].0'
print (d)
{'v1': 'v0', 'v2': 'v1', 'Time[s]': 'Time[s].0'}
df = df.rename(columns=d)
L = [x.groupby(x.columns[0]).mean()
if np.issubdtype(df[x.columns[1]].dtype, np.number)
else x.groupby(x.columns[0]).first()
for i, x in df.groupby(df.columns.str.split('.').str[-1], axis=1)]
df = pd.concat(L, axis=1)
print (df.head(10))
v.0 v.1 v.2
158.538395 NaN NaN Active
158.538515 NaN NaN Active
159.494550 NaN NaN Active
160.846210 0.0 NaN NaN
160.848080 NaN 7.0 NaN
161.146130 0.0 NaN NaN
161.148020 NaN 7.0 NaN
161.538245 27.0 NaN NaN
161.540085 NaN 7.0 NaN
162.015980 27.0 NaN NaN