mockito-core 版本:1.10.19
电源模拟版本:1.6.6
我尝试模拟一些静态方法,但输出让我感到困惑。这是我的代码:
class ClassWithStatics {
public static int getNextInt() {
return getInt() + 1;
}
public static int getInt() {
return 1;
}
public static long getTime() {
return System.currentTimeMillis();
}
}
@RunWith(PowerMockRunner.class)
@PrepareForTest({ClassWithStatics.class, System.class})
public class StubJustOneStatic {
@Test
public void test() {
PowerMockito.mockStatic(ClassWithStatics.class);
Mockito.when(ClassWithStatics.getInt()).thenReturn(0);
PowerMockito.mockStatic(System.class);
Mockito.when(System.currentTimeMillis()).thenReturn(12345L);
System.out.println("Next Int: " + ClassWithStatics.getNextInt());
System.out.println("Int: " + ClassWithStatics.getInt());
System.out.println("Time:" + ClassWithStatics.getTime());
}
}
输出为
Next Int: 0
Int: 0
Time:0
但是当我使用以下代码时,ClassWithStatics.getTime()
打印的正是我想要的。
@RunWith(PowerMockRunner.class)
@PrepareForTest({ClassWithStatics.class, System.class})
public class StubJustOneStatic {
@Test
public void test() {
// PowerMockito.mockStatic(ClassWithStatics.class);
// Mockito.when(ClassWithStatics.getInt()).thenReturn(0);
PowerMockito.mockStatic(System.class);
Mockito.when(System.currentTimeMillis()).thenReturn(12345L);
// System.out.println("Next Int: " + ClassWithStatics.getNextInt());
// System.out.println("Int: " + ClassWithStatics.getInt());
System.out.println("Time:" + ClassWithStatics.getTime());
}
}
多谢。
你是在嘲笑静态类,这意味着如果你没有显式定义 when((。then(( 行为,Mockito 将返回默认值(如果为 long,则为 0(。
您必须使用间谍来仅模拟某些方法,并让其他方法按实现的方式运行:
PowerMockito.spy(ClassWithStatics.class);
Mockito.when(ClassWithStatics.getInt()).thenReturn(5);
现在,当您调用:
PowerMockito.mockStatic(System.class);
Mockito.when(System.currentTimeMillis()).thenReturn(12345L);
System.out.println("Time:" + ClassWithStatics.getTime());
调用ClassWithStatics.getInt()
时应获得5
,调用ClassWithStatics.getTime()
时应12345L
。