下面的此方法用于打印链表中的内容,即Person对象。但是当我在命令提示符下运行时,它给出的不是 person 参数,而是给出位置。比如"Person@14991ad"。我做错了什么?
public class PhoneBook
{
Scanner input = new Scanner(System.in);
SLinkedList<Person> phoneList;
Node<Person> newNode;
public PhoneBook(){
phoneList = new SLinkedList<Person>();
}
public void printList(){
if(phoneList.size() == 0){
System.out.println("No Record is Found.");
}
Node tempNode = phoneList.head;
for(int i = 1; i <= phoneList.size; i++) {
System.out.print(tempNode.getElement());
if(i != phoneList.size)
System.out.println(" ");
tempNode = tempNode.getNext();
}
System.out.println();
}
}
下面是一个节点类。
public class Node<E> {
private E element;
private Node<E> next;
public Node() {
this(null, null);
}
public Node(E e, Node<E> n) {
element = e;
next = n;
}
public E getElement() {
return element;
}
public Node<E> getNext() {
return next;
}
public void setElement(E newElem) {
element = newElem;
}
public void setNext(Node<E> newNext) {
next = newNext;
}
}
我的链表实现。
public class SLinkedList<E> implements LinkedList<E> {
public Node<E> head;
public Node<E> tail;
public int size;
public SLinkedList() {
head = null;
tail = null;
size = 0;
}
public int size() {
return size;
}
public boolean isEmpty() {
return size == 0;
}
public void addFirst(Node<E> newNode) {
if(size == 0)
tail = newNode;
newNode.setNext(head);
head = newNode;
size++;
}
public void addLast(Node<E> newNode) {
newNode.setNext(null);
if(size == 0)
head = newNode;
if (size != 0)
tail.setNext(newNode);
tail = newNode;
size++;
}
public Node<E> removeFirst() {
Node<E> tempNode = null;
if (size != 0) {
if(size == 1)
tail = null;
tempNode = head;
head = head.getNext();
tempNode.setNext(null);
size--;
}
return tempNode;
}
public Node<E> removeLast() {
Node tempNode = head;
if(size == 0)
return null;
if(size == 1) {
head = null;
tail = null;
size--;
return tempNode;
}
for(int i=1; i<=size-2; i++) {
tempNode = tempNode.getNext();
}
Node tempNode2 = tail;
tail = tempNode;
tail.setNext(null);
size--;
return tempNode2;
}
public int searchList(E searchKey) {
if(size == 0)
return -1;
Node tempNode = head;
for(int i=1; i<=size; i++) {
if(tempNode.getElement().equals(searchKey))
return i;
tempNode = tempNode.getNext();
}
return -1;
}
public void printList() {
Node tempNode = head;
for(int i=1; i<=size; i++) {
System.out.print(tempNode.getElement());
if(i!=size) //if it is not last element
System.out.print(" - ");
tempNode = tempNode.getNext();
}
System.out.println();
}
}
人员类。
public class Person
{
private String name;
private String surname;
public String address;
public int cell;
public int home;
public int work;
public Person(){
}
public Person(String pName, String pSurname, String a, int cNumber, int hNumber, int wNumber)
{
name = pName;
surname = pSurname;
address = a;
cell = cNumber;
home = hNumber;
work = wNumber;
}
// Accessor methods:
public String getName(){
return name;
}
public String getSurname(){
return surname;
}
public String getAddress(){
return address;
}
public int getCell(){
return cell;
}
public int getHome(){
return home;
}
public int getWork(){
return work;
}
// Modifier methods:
public void setName(String name){
this.name = name;
}
public void setSurname(String surname){
this.surname = surname;
}
public void setAddress (String address){
this.address = address;
}
public void setCell (int cell){
this.cell = cell;
}
public void setHome (int home){
this.home = home;
}
public void setWork (int work){
this.work = work;
}
}
您没有显示Person
类的代码,但似乎您没有覆盖Object
的toString()
方法,该方法负责您看到的输出。 它不是内存地址,但它确实包含对象的哈希代码。
换句话说,此方法返回一个字符串,其值等于:
getClass().getName() + '@' + Integer.toHexString(hashCode())
在 Person
类中,重写toString()
并返回打印 Person
对象时要查看的String
。