音频设置输出 = 到变量

Question

你怎么能设置一个等于'O'或'-'的变量，然后将其放在如下所示的if语句中：

if variable == 'O':
    print 'hi'

你怎么能这样做：

import threading
from array import array
from Queue import Queue, Full
import pyaudio

CHUNK_SIZE = 1024
MIN_VOLUME = 500
BUF_MAX_SIZE = CHUNK_SIZE * 10

def main():
    stopped = threading.Event()
    q = Queue(maxsize=int(round(BUF_MAX_SIZE / CHUNK_SIZE)))
    listen_t = threading.Thread(target=listen, args=(stopped, q))
    listen_t.start()
    record_t = threading.Thread(target=record, args=(stopped, q))
    record_t.start()
    try:
        while True:
        listen_t.join(0.1)
        record_t.join(0.1)
    except KeyboardInterrupt:
        stopped.set()
    listen_t.join()
    record_t.join()

def record(stopped, q):
    while True:
        if stopped.wait(timeout=0):
            break
        chunk = q.get()
        vol = max(chunk)
        if vol >= MIN_VOLUME:
        # TODO: write to file
            print "O",
        else:
            print "-",

def listen(stopped, q):
    stream = pyaudio.PyAudio().open(
        format=pyaudio.paInt16,
        channels=2,
        rate=44100,
        input=True,
        frames_per_buffer=1024,
    )
    while True:
        if stopped.wait(timeout=0):
            break
        try:
            q.put(array('h', stream.read(CHUNK_SIZE)))
        except Full:
            pass  # discard

if __name__ == '__main__':
    main()

你能使用它，所以如果输出是"O"然后打印嗨？ 有人会为我编写代码吗，因为我一直在尝试编写这段代码，但我仍然无法使代码为我工作。 谢谢。

Answer 1

为了在 Python 中使用 if then 语句，首先我们需要根据需求和类型用适当的语法声明变量值。

s = "O"
if s == 'O':
    print 'hi'