因此，现在程序将从最大输出到最小，但是响应数量是错误的。似乎它仅输出最后一个正确的连续放置响应。代码是最后的。
它的作用：
Enter a integer rating between -20 and 5 for the product: 5
Enter a integer rating between -20 and 5 for the product: 4
Enter a integer rating between -20 and 5 for the product: 3
Enter a integer rating between -20 and 5 for the product: 2
Enter a integer rating between -20 and 5 for the product: 3
Enter a integer rating between -20 and 5 for the product: 1
Rating Number of Responses
------ -------------------
5 1
4 1
3 1
2 1
1 1
0 1
-1 1
-2 1
-3 1
-4 1
-5 1
-6 1
-7 1
-8 1
-9 1
-10 1
-11 1
-12 1
-13 1
-14 1
-15 1
-16 1
-17 1
-18 1
-19 1
-20 1
Process returned 0 (0x0) execution time : 13.643 s
Press any key to continue.
它应该做什么：
Enter a integer rating between -20 and 5 for the product: 5
Enter a integer rating between -20 and 5 for the product: 4
Enter a integer rating between -20 and 5 for the product: 3
Enter a integer rating between -20 and 5 for the product: 2
Enter a integer rating between -20 and 5 for the product: 3
Enter a integer rating between -20 and 5 for the product: 1
Rating Number of Responses
------ -------------------
5 1
4 1
3 2
2 1
1 1
0 0
-1 0
-2 0
-3 0
-4 0
-5 0
-6 0
-7 0
-8 0
-9 0
-10 0
-11 0
-12 0
-13 0
-14 0
-15 0
-16 0
-17 0
-18 0
-19 0
-20 0
Process returned 0 (0x0) execution time : 13.643 s
Press any key to continue.
另一个示例（错误地工作）：
Enter a integer rating between -20 and 5 for the product: 5
Enter a integer rating between -20 and 5 for the product: 4
Enter a integer rating between -20 and 5 for the product: 22
Not within range. Try again.
You have 3 more attempts before program outputs total:2
Enter a integer rating between -20 and 5 for the product: 2
Enter a integer rating between -20 and 5 for the product: 2
Enter a integer rating between -20 and 5 for the product: 2
Rating Number of Responses
------ -------------------
5 3
4 3
3 3
2 3
1 3
0 3
-1 3
-2 3
-3 3
-4 3
-5 3
-6 3
-7 3
-8 3
-9 3
-10 3
-11 3
-12 3
-13 3
-14 3
-15 3
-16 3
-17 3
-18 3
-19 3
-20 3
Process returned 0 (0x0) execution time : 8.426 s
Press any key to continue.
这里是...
#include <stdio.h> /* Necessary header */
#define MAX_RESPONDENTS 6
#define MIN_RESPONSE_VALUE -20 /* Abbreviated MiRV */
#define MAX_RESPONSE_VALUE 5 /* Abbreviated MaRV */
#define RESPONSE_VALUE 26 /* Equals |(MiRV)| + |(MaRV)| + 1 */
#define STOP 3
#define BREAK 1
int main(void)
{
CountRating();
return 0;
}
void CountRating()
{
int ratingCounters, rating[RESPONSE_VALUE] = {0}, Response, response;
for (ratingCounters = 0; ratingCounters < MAX_RESPONDENTS;)
{
int response, stop = STOP;
printf("Enter a integer rating between %d and %d for the product: ", MIN_RESPONSE_VALUE, MAX_RESPONSE_VALUE);
scanf("%d", &response);
if (response <= MAX_RESPONSE_VALUE && response >= MIN_RESPONSE_VALUE)
stop = STOP, Response = response;
else
{
int stopElse = stop;
if (stopElse < BREAK)
break;
else
{
do
{
printf("nNot within range. Try again.nYou have %d more attempts before program outputs total:", stop);
scanf("%d", &response);
printf("n");
--stop;
if (stop < BREAK)
break;
} while (response > MAX_RESPONSE_VALUE || response < MIN_RESPONSE_VALUE);
} if (stop < BREAK)
break;
}
++rating[Response];
++ratingCounters;
}
printf("nRating Number of Responsesn");
printf("------ -------------------");
for (ratingCounters = MAX_RESPONSE_VALUE; ratingCounters >= MIN_RESPONSE_VALUE; --ratingCounters)
{
printf("n%3d %23d", rating[RESPONSE_VALUE], rating[Response]);
}
}
您的数组索引从0开始，但是您的响应编号从-20到 5（26个值）。因此，当您写作时：
++rating[Response];
您无法访问您应该访问的数组元素。您需要做一些从输入的值减去min_response_value之类的事情。
您的输出循环每次都在打印相同的响应，因为您每次都访问相同的数组元素：
for (ratingCounters = MAX_RESPONSE_VALUE; ratingCounters >= MIN_RESPONSE_VALUE; --ratingCounters)
{
printf("n%3d %23d", rating[RESPONSE_VALUE], rating[Response]);
}
循环索引和数组索引被赋予诸如i之类的名称的原因有很多；此代码是一个检查程序。它使代码难以读取。您应该通过ratingCounters计算的某些值来索引。值之一应为 ratingCounters;另一个数组元素在ratingCounters计算的值上低音。
从您所知道的开始，没有预期的打印输出。验证您的代码可以执行您的期望。RESPONSE_VALUE和Response的值是多少？