通过 POST 方法在服务器上发送数据。并接收 JSON 响应。黑莓 - 回答。快乐编码
StringBuffer postData = new StringBuffer();
httpConn = (HttpConnection) Connector.open(URL);
httpConn.setRequestMethod(HttpConnection.POST);
postData.append("?username="+username);
postData.append("&password="+pass);
postData.append("&projectcode="+projectid);
String encodedData = postData.toString();
httpConn.setRequestProperty("Content-Language", "en-US");
httpConn.setRequestProperty("Content-Type","application/x-www-form-urlencoded");
httpConn.setRequestProperty("Content-Length",(new Integer(encodedData.length())).toString());
byte[] postDataByte = postData.toString().getBytes("UTF-8");
OutputStream out = httpConn.openOutputStream();
out.write(postDataByte);
out.close();
httpConn.getResponseCode();
is = httpConn.openInputStream();
StringBuffer buffer = new StringBuffer();
int ch = 0;
while (ch != -1) {
ch = is.read();
buffer.append((char) ch);
}
String json = buffer.toString();
Dialog.alert("Received Json: "+json);