我真的被难住了。当我运行程序时，我不断地遇到分段错误。我已经玩了一段时间了，我怀疑错误可能在于我的内存分配或释放。请帮忙：（我不知道我做错了什么。谢谢！
代码：
163 //Arguments: s1, delimter
164 //Returns a pointer to a char array containing entries for each token in s1. Think of this
165 //as a 2-D array. Each row contains a char* (token). This function creates a NEW char**
166 //variable and NEW char* variables for each token. Your method should be memory efficient.
167 //In other words, the space created for each token should be an exact fit for the space
168 //that token needs. If a token is five characters, allocate 5 bytes (plus null terminator).
169 //The function also writes the number of tokens into the numTokens variable.
170 char** tokenize(const char *s, char delimiter, int *numTokens){
171 //set variables
172 int i,j,a;
173 //alloacte space
174 char **arr = (char **)malloc((*numTokens) * sizeof(char *));
175 for (i=0; i<(*numTokens); i++){
176 arr[i] = (char *)malloc(50 * sizeof(char));
177 }
178
179 //while loop to search commence second search
180 //fill new 2d array
181 while(s[a] != ' '){
182 if(s[a] == delimiter){
183 j++;
184 i = 0;
185 }else{
186 arr[i][j] = s[a];
187 i++;
188 }
189 a++;
190 }// end while
191
192 //to end arr
193 arr[i][j] = ' ';
194
195 return arr;
196 }
测试：
137 char **test;
138 char *testFour;
139 int numTokens, *token;
140 testFour = (char *)calloc(50, sizeof(char));
141 sprintf(testFour, "check it with a space");
142 token = &numTokens;
143
144 test = tokenize(testFour, ' ', token);
145
146 if (compare(test[0], "check"))
147 printf("Test 1: Passn");
148 else
149 printf("Test 1: Failn");
150 if (compare(test[1], "it"))
151 printf("Test 2: Passn");
152 else
153 printf("Test 2: Failn");
154 if (compare(test[4], "space"))
155 printf("Test 3: Passn");
156 else
157 printf("Test 3: Failn");
free(testFour);
您使用的是在不初始化numTokens的情况下传递地址，然后在中使用该地址的值
char **arr = (char **)malloc((*numTokens) * sizeof(char *));
由于它没有初始化，该值可能是任何值，因此应该发生意外的事情，例如分段错误。
还有
- 不投射
malloc()的结果 - 定义为CCD_ 3