//user.dal
我在user.dal中有这两种方法,我正在尝试测试方法1,但是它在function1中有一个请求1(我想伪造这个结果),我正在使用sinon.stub
export async function function1(id) {
try {
const result1 = await User.findOne({ _id: id });
return result1;
} catch (error) {
throw new Error('invalid user');
}
}
export async function method1(id, date) {
const request1 = await function1(id); // this is not faking its results
const request2 = await function2(request1); // this need to fake the results also
return request2;
}
//user.test
describe.only('get all information ', () => {
const id = '5c842bd3cf058d36711c6a9e';
const user = {
_id: '5c76f49e6df2131fe23a100a',
};
const date = '2019-03-09';
let spyFunction1;
beforeEach(async () => {
spyFunction1 = sinon.stub(userDal, 'function1').returns('this is my result');
});
afterEach(async () => {
await userModel.deleteOne({ _id: id });
spyFunction1.restore();
});
it('Should get.', async () => {
const result = await userDal.function1(id);
console.log('this is working well', result);
const badResult = await userDal.method1(id, date);
console.log('-->>>', badResult); // when its call to method 1, its calling to the method and not using the mock that I impemented before
});
});
来自 import
doc:
静态
import
语句用于导入由另一个模块导出的绑定。
所以当您这样做时:
import * as userDal from './user.dal';
结果是userDal
包含与user.dal
模块导出的所有内容的绑定。
然后执行此操作:
sinon.stub(userDal, 'function1').returns('this is my result');
function1
绑定被返回'this is my result'
的stub
取代。
换句话说, function1
的模块导出已被Stub 。
所以当这条线运行时:
const result = await userDal.function1(id);
它调用function1
的模块导出(已固执),因此结果是'this is my result'
。
另一方面,此行运行时:
const badResult = await userDal.method1(id, date);
它进入method1
,然后运行以下行:
const request1 = await function1(id); // this is not faking its results
function1
,模块导出它直接调用 function1
。
为了能够在method1
中使用function1
和function2
,您必须调用其模块导出而不是直接调用它们。
对于Node.js
模块,模式如下所示:
const function1 = async function (id) { /* ... */ }
const function2 = async function (id) { /* ... */ }
const method1 = async function (id, date) {
const request1 = await exports.function1(id); // call the module export
const request2 = await exports.function2(request1); // call the module export
return request2;
}
exports.function1 = function1;
exports.function2 = function2;
exports.method1 = method1;
对于ES6模块,模式相似。请注意," ES6模块会自动支持循环依赖项",因此我们可以将模块返回自身以访问模块导出:
import * as userDal from 'user.dal'; // import module into itself
export async function function1(id) { /* ... */ }
export async function function2(id) { /* ... */ }
export async function method1(id, date) {
const request1 = await userDal.function1(id); // call the module export
const request2 = await userDal.function2(request1); // call the module export
return request2;
}
如果您遵循此模式并调用模块导出 for function1
和function2
从method1
内部调用CC_20打电话给method1
。
我认为您应该这样做:method1(id, date, function1, function2)
。从本质上讲,您将作为参数传递在函数1中。然后,在测试中,您可以通过模拟功能或存根来进行测试。
export async function function1(id) {
try {
const result1 = await User.findOne({ _id: id });
return result1;
} catch (error) {
throw new Error('invalid user');
}
}
export async function method1(id, date, function1, function2) {
const request1 = await function1(id);
const request2 = await function2(request1);
return request2;
}