如何将PHPunit与testrail集成

Question

我想将我的功能测试结果与TestRail集成。由于测试轨接受状态更新意味着测试是成功还是失败，无法与之集成。但是 PHPunit 函数如 assertEqual、assertTrue 等不返回任何值。我们该怎么做呢？

public function testGetItem()
{
    $this->specify("Verify the functionality of the method ", function ($itemId, $orgId, $expectedResult) {
    $result = $this->itemRepository->getItemInfo($ItemId , $orgId);
    //$this->assertEquals($expectedResult , $result) 
    $testRail=new TestRailIntegration();
    if($this->assertEquals($expectedResult , $result)){
        $testRail->postResultsToTestRail("34530","1");
    } else{
        $testRail->postResultsToTestRail("34530","");
    }
    //34530 is testrail id
}

当测试失败时，它不会转到 ELSE 条件。

Answer 1

一个简单的答案是捕获异常，发布结果并重新抛出异常。

public function testGetItem()
{
    $this->specify("Verify the functionality of the method ", function ($itemId, $orgId, $expectedResult) {
    $testRail = new TestRailIntegration();
    try {
        $result = $this->itemRepository->getItemInfo($ItemId , $orgId);
        $this->assertEquals($expectedResult, $result);
        $testRail->postResultsToTestRail("34530", "1");
    } catch (Exception $e) {
        $testRail->postResultsToTestRail("34530", "");
        throw $e;
    }
}