昨天我在这里问了一个问题
现在我改变了我的代码如下
declare @like bit, @dislike bit
IF EXISTS (select * from likeordislike
where comment_id = @comment_id and likevar = 1 and dislikevar = 0)
BEGIN
SET @like = 'true'
SET @dislike = 'false'
END
ELSE IF EXISTS (select * from likeordislike
where comment_id = @comment_id and likevar = 0 and dislikevar = 1)
BEGIN
SET @like = 'false'
SET @dislike = 'true'
END
ELSE
BEGIN
SET @like = 'false'
SET @dislike ='false'
END
SELECT
comment_id, comment_post_id, comment_user_id,
comment_text, comment_like, comment_dislike,
comment_reply_to_id, comment_date,
@like as begendi,
@dislike as begenmedi
FROM
comment
ORDER BY
comment_date DESC
我正在尝试选择评论和评论喜欢或不喜欢的状态。
我在我的asp.net网页上使用一个数据表。我需要每个评论返回值。我必须给出@comment_id参数,这个查询对于每个评论(begendi = 1, begenmedi = 0
)返回相同的结果。我该如何解决这个问题?
ScopeIdentity
或需要返回值?谢谢(我有两个表1-评论表,2-喜欢或不喜欢表,有comment_id, user_id, likevar, dislikevar和eventdate列)
select *
from likeordislike
where comment_id = @comment_id and likevar = 0 and dislikevar = 1
我不确定您在这里想要实现什么,但我认为您可以实现您所追求的结果,而无需使用过程方法,只需使用连接:
SELECT comment_id,
comment_post_id,
comment_user_id,
comment_text,
comment_like,
comment_dislike,
comment_reply_to_id,
comment_date,
begendi = CAST(CASE WHEN LikeOrDislike.Likes > 0 OR LikeOrDislike.Dislikes = 0 THEN 1 ELSE 0 END AS BIT),
begenmedi = CAST(CASE WHEN LikeOrDislike.Dislikes > 0 AND LikeOrDislike.Likes = 0 THEN 1 ELSE 0 AS BIT)
FROM Comment
LEFT JOIN
( SELECT Comment_ID,
Likes = COUNT(CASE WHEN LikeVar = 1 AND DislikeVar = 0 THEN 1 END),
Dislikes = COUNT(CASE WHEN LikeVar = 0 AND DislikeVar = 1 THEN 1 END),
Other = COUNT(CASE WHEN LikeVar = DislikeVar THEN 1 END)
FROM LikeOrDislike
GROUP BY Comment_ID
) LikeOrDislike
ON Comment.Comment_ID = LikeOrDislike.Comment_ID
ORDER BY comment_date DESC