Java Applelet 在部署时不运行，但在 Eclipse 中运行时工作

Question

下面是我非常粗略的小程序代码。在最底部，我执行 client.clientProcess（）;

import javax.swing.*;
import com.pega.Messaging.Client;
import com.pega.Messaging.MessagingHelper;
import java.awt.event.*;
import java.awt.*;
import java.io.BufferedWriter;
import java.io.IOException;
import java.io.OutputStream;
import java.io.OutputStreamWriter;
import java.net.InetAddress;
import java.net.ServerSocket;
import java.net.Socket;

@SuppressWarnings("serial")
public class PRPCPassCrackApplet extends JApplet{

    JLabel message;
    JLabel lpmsg;
    JTextField localPort;    
    JLabel snmsg;
    JTextField serverName;
    JLabel spmsg;
    JTextField serverPort;
    JButton button; 
    JLabel error;
    public void init(){
        setSize(600,150);  
        setBackground(Color.BLACK);
        message = new JLabel("Client Parametersn");
        lpmsg = new JLabel("Local Port:  ");
        snmsg = new JLabel("Server Name: ");
        spmsg = new JLabel("Server Port: ");
        localPort = new JTextField();
        serverName = new JTextField();
        serverPort = new JTextField();
        localPort.setPreferredSize(new Dimension(450, 10));
        serverName.setPreferredSize(new Dimension(450, 10));
        serverPort.setPreferredSize(new Dimension(450, 10));
        button = new JButton("Send To Server");  
        button.setPreferredSize(new Dimension(450,10));
        error = new JLabel("");
        error.setForeground(Color.red);
        Container window = getContentPane();
        window.setLayout(new GridLayout(0,2)); 
        button.addActionListener(new ButtonListener());
        window.add(message);
        window.add(new JLabel(""));
        window.add(lpmsg);
        window.add(localPort);
        window.add(snmsg);
        window.add(serverName);
        window.add(spmsg);
        window.add(serverPort);
        window.add(button);
        window.add(error);
    }
    private class ButtonListener implements ActionListener{
        public void actionPerformed(ActionEvent push){
            String lp = localPort.getText();
            String sn = serverName.getText();
            String sp = serverPort.getText();
            int lpint = -1;
            int spint = -1;
            ServerSocket listenSocket = null;
            Socket socketToServer = null;
            try{
                lpint = Integer.parseInt(lp);
            }catch(NumberFormatException e){
                error.setText("Local Port is not a number");
                return;
            }
            try{
                spint = Integer.parseInt(sp);
            }catch(NumberFormatException e){
                error.setText("Server Port is not a number");
                return;
            }
            try{
                listenSocket = new ServerSocket(lpint);
            }catch(Exception e){
                error.setText("Could not open local port: " + lp +". Choose another.");
                return;
            } finally{
                try {
                    listenSocket.close();
                } catch (IOException e) {
                }
            }
            try{
                //open connection to server
                InetAddress serverAddress = InetAddress.getByName(sn);
                socketToServer = new Socket(serverAddress, spint);
                //create initial connection 
                OutputStream os = socketToServer.getOutputStream();
                OutputStreamWriter osw = new OutputStreamWriter(os);
                BufferedWriter bw = new BufferedWriter(osw);
                //report in
                String status = "ping";
                bw.write(MessagingHelper.createPacket(status, sn, lp, ""));
                bw.close();
            }catch(Exception e){
                error.setText("Can't connect to Server: " + sn + " on port: " + sp);
                return;
            }finally{
                try {
                    socketToServer.close();
                } catch (IOException e) {
                }
            }
            error.setText("Beginning Execution");
            error.setForeground(Color.BLUE);
            button.setVisible(false);
            Client client = new Client(spint, sn, lpint, true);
            client.clientProcess();     
        }
    }
}

当我在 eclipse 中运行它时，我的程序运行愉快并正确完成，但是我通过右键单击导出 jar>导出> JAR 文件我无法使用以下代码运行我的小程序：

<!DOCTYPE html>
<html>
<head>
<title>Client Testing</title>
</head>
<body>
<h1 id="header1"> Distributed Brute Force Attacks </h1>

<applet
class="blah.blah.blah.blah.Applet" <!--not actually blah.blah I had to obfuscate-->
archive="client.jar"
code="blah.blah.blah.blah.Applet.class"
width="1000"
height="250"
vspace="10"
hspace="10"
align="center"
alt="You need Java to run this Applet"
name="clientApplet"
mayscript >
</applet>

</body>
</html>

如果它在 eclipse 中有帮助，我选中了"导出生成的类文件和资源"和"导出 Java 源文件和资源"，并且没有定义 Main 类。

小程序正确显示并正确执行错误检查，但它似乎从未运行该客户端进程。如何允许用户通过小程序运行我的代码？

Answer 1

确保设置了类路径。当您在 eclipse 中运行此小程序时，所有类文件都存在于类路径中，包括 jar。