PHP比较今天的日期与(多维)数组中的日期

Question

我有一个日期数组，我想知道是否可以搜索数组并删除今天日期之前的任何项目，并保留其余部分?

这是我的数组

Array
(
    [0] => Array
        (
            [date] => 2013-07-14
        )
    [1] => Array
        (
            [date] => 2013-08-31
        )
    [2] => Array
        (
            [date] => 2013-09-15
        )
    [3] => Array
        (
            [date] => 2013-10-12
        )
    [4] => Array
        (
            [date] => 2013-10-16
        )
    [5] => Array
        (
            [date] => 2013-10-19
        )
    [6] => Array
        (
            [date] => 2013-10-23
        )
    [7] => Array
        (
            [date] => 2013-10-26
        )
    [8] => Array
        (
            [date] => 2013-10-30
        )
    [9] => Array
        (
            [date] => 2013-09-07
        )
    [10] => Array
        (
            [date] => 2013-08-14
        )
    [11] => Array
        (
            [date] => 2013-08-24
        )
    [12] => Array
        (
            [date] => 2013-09-11
        )
    [13] => Array
        (
            [date] => 2013-09-28
        )
    [14] => Array
        (
            [date] => 2013-10-05
        )
)

Answer 1

像这样:

$buffer = array();
foreach ($dates as $element) {
    if (strtotime($element['date']) >= time()) {
        $buffer[] = $element;
    }
}

Answer 2

如何循环遍历和比较日期与实际需要的数据，并构建一个新的过滤数组?

$newarray = array();
foraeach($array as $data)
{
     if($data['date'] >= $yourdate)
     {
         $newarray] = $data;
     }
}

Answer 3

array_walk函数允许您定义一个回调函数来运行在数组中的每个项上。