获取不断变化的整数的最新 Int 2 值

Question

我正在尝试检查不断变化的速度整数中的值，我要检查的值是当前值和它之前的值，我有此代码，但由于某种原因它不起作用。 我的问题是如何有效地保存不断变化的速度整数的最新 2 个值

这是我的代码

int CurrentValue; // The Integer is already defined and initialized, this is the latest value of it
int PriorValue; // this value is the one that was prior to the current one
CurrentValue = ChangingInt; // here we save the current Speed value in ChangingInt
if (CurrentValue != ChangingInt){
PriorValue = CurrentValue; /* replacing the CurrentValue value as the prior one
since it has changed according to the if statement */
}

Answer 1

您可以添加一个temp变量来存储CurrentValue的值。

int CurrentValue;
int PriorValue;
int temp = CurrentValue; //Add a temp variable to store CurrentValue.
CurrentValue = ChangingInt;        
PriorValue = temp;

Answer 2

int ChangingInt = ...          // ChangingInt = A, PriorValue = B, CurrentValue = C
...
int PriorValue = CurrentValue  // ChangingInt = A, PriorValue = C, CurrentValue = C
int CurrentValue = ChangingInt // ChangingInt = A, PriorValue = B, CurrentValue = A

在此运行之后，我们将不需要PriorValue，因为我们只需要最后两个值，因此我们应该首先通过将其更改为CurrentValue来重新分配PriorValue(因为CurrentValue需要成为新的PriorValue(。然后，我们可以将CurrentValue更改为ChangingInt.