热以添加JPA标准中另一个对象的参数列表

Question

我有一个班级主任

   public class Director {
      private Long id;
      @OneToOne(cascade = CascadeType.ALL)
      @JoinColumn(name="transacao_id")
      private Company company;
      private Date registrationDate;
       ...
   }

我有一个班级公司

   public class Company {
      private Long id;
      private String cnpj;
      private String description;
       ...
   }

我需要在谓词中添加另一个过滤器...

我需要从导演中获取列表，通过使用JPA谓词列表进行过滤，例如：

private Predicate[] criarRestricoes(FilterDTO filter, CriteriaBuilder builder, Root<Director> root) {
        List<Predicate> predicates = new ArrayList<>();
        Date today = new Date();
        if (filter.getRegistrationDate() != null) {
            predicates.add(builder.between(root.get("registrationDate").as(Date.class), today, filter.dateParam));
        } 
       if (!StringUtils.isEmpty(filter.getCnpj())) {
            predicates.add(builder.equal(???????????, ???????????????);
        } 
        return predicates.toArray(new Predicate[predicates.size()]);
    }

Answer 1

builder.equal(root.join("company").get("cnpj"), filter.getCnpj());