我想要一个函数来创建一个"正方形"结构元素,例如:
Mat explicit_kernel = (Mat_<int>(5, 5) <<
-1, -1, -1, -1, -1,
-1, 1, 1, 1, -1,
-1, 1, 1, 1, -1,
-1, 1, 1, 1, -1,
- 1, -1, -1, -1, -1);
所以我试图做一个丑陋的循环:
Mat generate_kernel(int size)
{
if (size % 2 == 0)
{
printf("Input %i, not even, replaced by %in", size, size + 1);
size++;
}
Mat out = Mat::ones(size + 2, size + 2, CV_8S);
for (int i = 0; i <= size + 1; i++)
{
for (int j = 0; j <= size + 1; j++)
{
if (i == 0 || i == size - 1)
{
out.at<int>(i, j) = -1;
}
else
{
if (j == 0 || j == size - 1)
{
out.at<int>(i, j) = -1;
}
}
}
}
//Mat out = getStructuringElement(MORPH_RECT, Size(size, size), Point(-1, -1));
return out;
}
但是我有一个"违规书写错误",无论如何我正在寻找一个更容易的需求,代码的主要目的是在循环中制作结构元素: - 大小1的正方形,尺寸3 ...谢谢:)
我找到了一个解决方案,考虑到CV :: MAT是指针,并且创建一个子矩阵
Mat generate_kernel(int size)
{
if (size % 2 == 0)
{
printf("Input %i, not even, replaced by %in", size, size + 1);
size++;
}
Mat out = -1 * Mat::ones(size + 2, size + 2, CV_8S);
Mat center = Mat(out, Rect(1, 1, size, size));
center = Mat::ones(size, size, CV_8S);
return out;
}
这可能已经通过cv::copyMakeBorder
方法来处理。
#include <iostream>
#include <opencv2/opencv.hpp>
using namespace std;
using namespace cv;
Mat generate_kernel(int size, int outer_size=1)
{
if (size % 2 == 0)
{
printf("Input %i, not even, replaced by %in", size, size + 1);
size++;
}
Mat out = Mat::ones(size, size, CV_8S);
copyMakeBorder(out,
out,
outer_size, // top
outer_size, // bottom
outer_size, // left
outer_size, // right
BORDER_CONSTANT,
Scalar(-1.0));
return out;
}
int main(int argc, const char * argv[]) {
cout << "Size 1: " << generate_kernel(1) << endl;
cout << "Size 3: " << generate_kernel(3) << endl;
cout << "Size 5: " << generate_kernel(5) << endl;
return 0;
}
它将生成以下....
Size 1: [ -1, -1, -1;
-1, 1, -1;
-1, -1, -1]
Size 3: [ -1, -1, -1, -1, -1;
-1, 1, 1, 1, -1;
-1, 1, 1, 1, -1;
-1, 1, 1, 1, -1;
-1, -1, -1, -1, -1]
Size 5: [ -1, -1, -1, -1, -1, -1, -1;
-1, 1, 1, 1, 1, 1, -1;
-1, 1, 1, 1, 1, 1, -1;
-1, 1, 1, 1, 1, 1, -1;
-1, 1, 1, 1, 1, 1, -1;
-1, 1, 1, 1, 1, 1, -1;
-1, -1, -1, -1, -1, -1, -1]