国际象棋/Java："Moved Out Of Check" 在 Java 中签入

Question

所以我已经在这个国际象棋应用程序上工作了大约一个星期(每天几个小时(——我似乎遇到了一个障碍。所有的棋子都按原样移动，有碰撞和所有——我有晋升和铸造工作，我可以成功地检查是否受到控制。

但是，我似乎无法检查此举是否合法地不受控制。我目前的方法是移动棋子 - 检查这个人是否仍在检查中，如果没有，那么移动是合法的。

但是，似乎当我这样做时，它无法正确计算虚假移动后的支票。

任何帮助都会很棒。

public abstract class Piece {
private Type type = Type.BLANK;
private int locX, locY, preX, preY;
private Player player;
private boolean moved = false;
Piece(Type type, int locX, int locY, Player player) {
    this.locX = locX;
    this.locY = locY;
    this.player = player;
    this.type = type;
}
public void movePiece(int x, int y) {
    if (player.isTurn()) {
        if (isLegalMove(x, y)) {
            if (checkCollision(x, y)) {
                if (clearsCheck(x, y)) {
                    preX = locX;
                    preY = locY;
                    setLoc(x, y);
                    specialPreMove(x, y);
                    moved = true;
                    Chess.chessBoard.bitBoard[preX][preY] = null;
                    if (Chess.chessBoard.bitBoard[x][y] != null) {
                        Chess.chessBoard.bitBoard[x][y].getPlayer().pieces.remove(Chess.chessBoard.bitBoard[x][y]);
                    }
                    Chess.chessBoard.bitBoard[x][y] = this;
                    specialPostMove(x, y);
                    Chess.chessBoard.getGui().repaint();
                    Chess.changeTurns();
                }
            }
        }
    }
}
protected void specialPreMove(int x, int y) {}
protected void specialPostMove(int x, int y) {}
protected abstract boolean checkCollision(int x, int y);
protected abstract boolean isLegalMove(int x, int y);
private boolean clearsCheck(int x, int y) {
    boolean checkCk = false;
    preX = locX;
    preY = locY;
    setLoc(x, y);
    Piece locPiece = null;
    Chess.chessBoard.bitBoard[preX][preY] = null;
    if (Chess.chessBoard.bitBoard[x][y] != null) {
        locPiece = Chess.chessBoard.bitBoard[x][y];
        Chess.chessBoard.bitBoard[x][y].getPlayer().pieces.remove(Chess.chessBoard.bitBoard[x][y]);
        System.out.println("Piece there: " + locPiece);
    }
    Chess.chessBoard.bitBoard[x][y] = this;
    System.out.println(Chess.chessBoard.bitBoard[x][y]);
    Chess.chessBoard.getGui().repaint();
    Chess.checkCheck();
    checkCk = !player.inCheck();
    setLoc(preX, preY);
    Chess.chessBoard.bitBoard[preX][preY] = this;
    if (locPiece != null) {
        Chess.chessBoard.bitBoard[x][y] = locPiece;
        Chess.chessBoard.bitBoard[x][y].getPlayer().pieces.add(Chess.chessBoard.bitBoard[x][y]);
    } else {
        Chess.chessBoard.bitBoard[x][y] = null;
    }
    System.out.println(checkCk);
    return checkCk;
}
public ArrayList<Move> getLegalMoves() {
    ArrayList<Move> moves = new ArrayList<Move>();
    for (int row = 0; row < 8; row++) {
        for (int col = 0; col < 8; col++) {
            if (isLegalMove(row, col) && checkCollision(row, col)) {
                moves.add(new Move(row, col));
            }
        }
    }
    return moves;
}

是 piece 类，然后是 check 方法

public static void checkCheck() {
    for (Move m : player1.getLegalMoves()) {
        if (m.getX() == player2.getKing().getLocX()
                && m.getY() == player2.getKing().getLocY()) {
            player2.setCheck(true);
            System.out.println("IN CHECK PLAYER 2");
            break;
        }
    }
    for (Move m : player2.getLegalMoves()) {
        if (m.getX() == player1.getKing().getLocX()
                && m.getY() == player1.getKing().getLocY()) {
            player1.setCheck(true);
            System.out.println("IN CHECK PLAYER 1");
            break;
        }
    }
}

然后这里有一些其他有用的东西

public class Player {
private Color color;
private Direction direction;
private boolean turn;
private boolean check = false;
public ArrayList<Piece> pieces = new ArrayList<>();
public Player(Color color, Direction direction) {
    this.color = color;
    this.turn = false;
    this.direction = direction;
}
public ArrayList<Move> getLegalMoves() {
    ArrayList<Move> moves = new ArrayList<>();
    for (Piece p : pieces) {
        for (Move m : p.getLegalMoves()) {
            moves.add(m);
        }
    }
    return moves;
}
public Piece getKing() {
    for (Piece p : pieces) {
        if (p.getType() == Type.KING) {
            return p;
        }
    }
    return null;
}

Answer 1

看起来一旦

你设置了一个玩家处于选中状态，你以后就不会将他的状态设置为未选中。

public static void checkCheck() {
  boolean isInCheck = false;
  for (Move m : player1.getLegalMoves()) {
            if (m.getX() == player2.getKing().getLocX()
            && m.getY() == player2.getKing().getLocY()) {
                isInCheck = true;
                System.out.println("IN CHECK PLAYER 2");
                break;
            }
    }
        player2.setCheck(isInCheck);
    isInCheck = false;
    for (Move m : player2.getLegalMoves()) {
        if (m.getX() == player1.getKing().getLocX()
        && m.getY() == player1.getKing().getLocY()) {
            isInCheck = true;
            System.out.println("IN CHECK PLAYER 1");
            break;
        }
    }
    player1.setCheck(isInCheck);
}