当我运行Python Turtle游戏时，图形窗口停止响应

Question

我是乌龟和编程的新手，并且想制作一个标签游戏。有两个用户，一个是跑步者，一个是追逐者(鲍勃和菲尔(。当追逐者靠近跑步者(使用距离公式检测到(时，程序将其设置回原始的起始位置。但是，每当我运行该程序时，Turtle图形窗口都会冻结并停止响应，最终导致我关闭程序。谁能帮助我确定这个问题？

import turtle
import math
bob = turtle.Turtle()
wn = turtle.Screen()
wn.bgcolor("black")
wn.setup(width = 700, height = 700)
wn.tracer()
border_pen = turtle.Turtle()
border_pen.speed(0)
border_pen.color("white")
border_pen.penup()
border_pen.setposition(-300,-300)
border_pen.pendown()
border_pen.pensize(3)
for side in range(4):
    border_pen.fd(600)
    border_pen.lt(90)
border_pen.hideturtle()
bob.shape("triangle")
bob.speed(0)
bob.color("blue")
bob.penup()
bob.setpos(-50, 0)
def draw():
    bob.penup()
def nodraw():
    bob.pendown()
def fd():
    bob.fd(20)
    if bob.xcor() > 280:
        bob.setx(280)
    if bob.ycor() > 280:
        bob.sety(280)
    if bob.xcor() < -280:
        bob.setx(-280)
    if bob.ycor() <- 280:
        bob.sety(-280)
def right():
    bob.right(90)
def left():
    bob.left(90)
turtle.listen()
turtle.onkey(left, "Left")
turtle.onkey(fd, "Up")
turtle.onkey(right, "Right")
phil = turtle.Turtle()
phil.speed(0)
phil.penup()
phil.shape("triangle")
phil.color("red")
phil.setpos(50, 0)
def fdp():
    phil.fd(20)
    if phil.xcor() > 280:
        phil.setx(280)
    if phil.ycor() > 280:
        phil.sety(280)
    if phil.xcor() < -280:
        phil.setx(-280)
    if phil.ycor() <- 280:
        phil.sety(-280)
def rightp():
    phil.right(90)
def leftp():
    phil.left(90)
turtle.listen()
turtle.onkey(leftp, "a")
turtle.onkey(fdp, "w")
turtle.onkey(rightp, "d")

def isCollision(t1, t2):
    distance = math.sqrt(math.pow(t1.xcor()-t2.xcor(),2)+math.pow(t1.ycor()-t2.ycor(),2))
    if distance < 20:
        return True
    else:
        return False
while True:
    if isCollision(bob, phil):
        bob.setposition(-50, 0)
        phil.setposition(50, 0)

turtle.done()

Answer 1

您的原始代码和我尝试在下面尝试解决的建议答案存在问题。具体来说：您不需要计算海龟之间的距离，他们已经知道如何做。您和其他人的使用tracer()毫无意义，因为您没有update()调用；鲍勃和菲尔之间的碰撞应该是对称的，但答案之一考虑到鲍勃碰撞菲尔，但菲尔与鲍勃相撞。答案之一似乎不了解turtle.done()的性质。

from turtle import Screen, Turtle, mainloop
def bob_left():
    bob.left(90)
def bob_forward():
    bob.forward(20)
    if bob.xcor() > 280:
        bob.setx(280)
    elif bob.xcor() < -280:
        bob.setx(-280)
    if bob.ycor() > 280:
        bob.sety(280)
    elif bob.ycor() < -280:
        bob.sety(-280)
    checkCollision()
def bob_right():
    bob.right(90)
def phil_left():
    phil.left(90)
def phil_forward():
    phil.forward(20)
    if phil.xcor() > 280:
        phil.setx(280)
    elif phil.xcor() < -280:
        phil.setx(-280)
    if phil.ycor() > 280:
        phil.sety(280)
    elif phil.ycor() < -280:
        phil.sety(-280)
    checkCollision()
def phil_right():
    phil.right(90)
def isCollision(t1, t2):
    return t1.distance(t2) < 20
def checkCollision():
    if isCollision(bob, phil):
        bob.setposition(-50, 0)
        phil.setposition(50, 0)
screen = Screen()
screen.bgcolor('black')
screen.setup(width=700, height=700)
border_pen = Turtle(visible=False)
border_pen.speed('fastest')
border_pen.color('white')
border_pen.pensize(3)
border_pen.penup()
border_pen.setposition(-300, -300)
border_pen.pendown()
for _ in range(4):
    border_pen.fd(600)
    border_pen.lt(90)
bob = Turtle('triangle')
bob.speed('fastest')
bob.color('blue')
bob.penup()
bob.setpos(-50, 0)
phil = Turtle('triangle')
phil.speed('fastest')
phil.color('red')
phil.penup()
phil.setposition(50, 0)
screen.onkey(bob_left, 'Left')
screen.onkey(bob_forward, 'Up')
screen.onkey(bob_right, 'Right')
screen.onkey(phil_left, 'a')
screen.onkey(phil_forward, 'w')
screen.onkey(phil_right, 'd')
screen.listen()
mainloop()

Answer 2

审查后，这应该有效：

import turtle
import math
bob = turtle.Turtle()
wn = turtle.Screen()
wn.bgcolor("black")
wn.setup(width = 700, height = 700)
wn.tracer()
border_pen = turtle.Turtle()
border_pen.speed(0)
border_pen.color("white")
border_pen.penup()
border_pen.setposition(-300,-300)
border_pen.pendown()
border_pen.pensize(3)
for side in range(4):
    border_pen.fd(600)
    border_pen.lt(90)
border_pen.hideturtle()
bob.shape("triangle")
bob.speed(0)
bob.color("blue")
bob.penup()
bob.setpos(-50, 0)
def draw():
    bob.penup()
def nodraw():
    bob.pendown()
def fd():
    bob.fd(20)
    if bob.xcor() > 280:
        bob.setx(280)
    if bob.ycor() > 280:
        bob.sety(280)
    if bob.xcor() < -280:
        bob.setx(-280)
    if bob.ycor() <- 280:
        bob.sety(-280)
    distance = math.sqrt(math.pow(bob.xcor()-phil.xcor(),2)+math.pow(bob.ycor()-phil.ycor(),2))
    print(distance)
    if distance < 20:
        bob.setposition(-50, 0)
        phil.setposition(50, 0)
def right():
    bob.right(90)
def left():
    bob.left(90)
turtle.listen()
turtle.onkey(left, "Left")
turtle.onkey(fd, "Up")
turtle.onkey(right, "Right")
phil = turtle.Turtle()
phil.speed(0)
phil.penup()
phil.shape("triangle")
phil.color("red")
phil.setpos(50, 0)
def fdp():
    phil.fd(20)
    if phil.xcor() > 280:
        phil.setx(280)
    if phil.ycor() > 280:
        phil.sety(280)
    if phil.xcor() < -280:
        phil.setx(-280)
    if phil.ycor() <- 280:
        phil.sety(-280)
def rightp():
    phil.right(90)
def leftp():
    phil.left(90)
turtle.listen()
turtle.onkey(leftp, "a")
turtle.onkey(fdp, "w")
turtle.onkey(rightp, "d")
turtle.done()

Answer 3

缩进您的 turtle.done()在while循环内。这将解决您的冻结问题。这样：

while True:
    if isCollision(bob, phil):
        bob.setposition(-50, 0)
        phil.setposition(50, 0)
    turtle.done()

您也可以删除while循环，因为您实际上不需要它才能使用if语句。这样：

if isCollision(bob, phil):
    bob.setposition(-50, 0)
    phil.setposition(50, 0)
turtle.done()