对XSLT中每个嵌套的3个计数求和

Question

我有以下XSLT:

<?xml version="1.0"?>
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns="http://www.3ds.com/xsd/XPDMXML">
<xsl:output method="text" doctype-public="XSLT-compat" encoding="ISO-8859-1"/>
<xsl:template match="/">
<xsl:for-each select="/foo/bar/AAA[Owned/text()='1']">
<xsl:variable name="vOP">
<xsl:value-of select="./Instancing"/>
</xsl:variable>
<xsl:for-each select="/foo/bar/BBB[Owned[text()=$vOP]]">
<xsl:variable name="vTO">
<xsl:value-of select="./Instancing"/>
</xsl:variable>
<xsl:for-each select="/foo/bar/CCC[Owned[text()=$vTO]]">
<xsl:variable name="vIE">
<xsl:value-of select="./Instancing"/>
</xsl:variable>
<xsl:text>"COUNT": </xsl:text><xsl:value-of select="count(/foo/buzz/DDD[Owned[text()=$vIE]])"/><xsl:text>,</xsl:text>
</xsl:for-each>
</xsl:for-each>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>

这是一个样本输入

<?xml version='1.0' encoding='utf-8'?>
<foo>
<bar>
<AAA>
<Owned>1</Owned>
<Instancing>2</Instancing>
</AAA>
<BBB>
<Owned>2</Owned>
<Instancing>3</Instancing>
</BBB>
<CCC>
<Owned>3</Owned>
<Instancing>4</Instancing>
</CCC>
<CCC>
<Owned>3</Owned>
<Instancing>5</Instancing>
</CCC>
<CCC><Owned>4</Owned></CCC>
</bar>
<buzz>
<DDD><Owned>4</Owned></DDD>
<DDD><Owned>4</Owned></DDD>
<DDD><Owned>5</Owned></DDD>
<DDD><Owned>3</Owned></DDD>
<CCC><Owned>4</Owned></CCC>
</buzz>
</foo>

有没有办法获得最近一次value-of调用的总值(SUM(？还有可能把前臂全部切除？

输出应该是3(2+1(。

Answer 1

您可以将第一次计算的结果存储在变量中，然后将变量的值相加(并输出它们：

<xsl:template match="/">
<xsl:variable name="counts" as="element(count)*">
<xsl:for-each select="/foo/bar/AAA[Owned = 1]">
<xsl:variable name="vOP" select="Instancing"/>
<xsl:for-each select="/foo/bar/BBB[Owned = $vOP]">
<xsl:variable name="vTO" select="Instancing"/>
<xsl:for-each select="/foo/bar/CCC[Owned = $vTO]">
<xsl:variable name="vIE" select="Instancing"/>
<count>
<xsl:value-of select="count(/foo/buzz/DDD[Owned = $vIE])"/>
</count>
</xsl:for-each>
</xsl:for-each>
</xsl:for-each>            
</xsl:variable>
<xsl:value-of select="$counts/concat('COUNT:', .), concat('SUM:', sum($counts))" separator=","/>
</xsl:template>

至于使用更紧凑的代码，您可以使用键来遵循交叉引用：

<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="text" indent="yes"/>
<xsl:key name="ref" match="bar/*" use="Owned"/>
<xsl:key name="buzz" match="buzz/DDD" use="Owned"/>
<xsl:template match="/">
<xsl:variable name="counts" as="element(count)*">
<xsl:for-each select="key('ref', key('ref', key('ref', '1')/Instancing)/Instancing)">
<count>
<xsl:value-of select="sum(count(key('buzz', Instancing)))"/>
</count>
</xsl:for-each>
</xsl:variable>
<xsl:value-of select="$counts/concat('COUNT:', .), concat('SUM:', sum($counts))" separator=","/>
</xsl:template>
</xsl:stylesheet>

https://xsltfiddle.liberty-development.net/nc4NzRs/4

我不知道您的输入数据有多可变，也许bar的不同子元素需要不同的键，对于您的样本数据，单个键就足够了。