如何连接远端流并将其发送到另一个对等端

Question

我想要附加远程流并将其发送到另一个对等端，像这样附加远程流:

firstPeer.onaddstream = function(remoteSteam) {
  otherPeer.addStream(remoteStream);  /* attaching remote stream */
};

但是它不工作!(我无法在其他浏览器中接收此流)

谁能告诉我如何连接远程流?如何将远端流发送到另一个对等端?

谢谢!

Answer 1

我之前测试过。但是，如果附加了" remote stream "，则stream不流动。

我发现chrome在创建offer sdp时错过了许多属性，同时offer sdp被设置为" recvonly "而不是" sendrecv "。

在最新的chrome金丝雀中，您可以像这样附加"远程流"。

var newStream = new webkitMediaStream(remoteStream);
peer2.addStream(newStream);

或其他:

var newStream = new webkitMediaStream([remoteStream.getAudioTracks(),remoteStream.getVideoTracks()]);
peer2.addStream(newStream);

在旧chrome中:

var newStream = new webkitMediaStream(remoteStream.audioTracks, remoteStream.videoTracks);
peer2.addStream(newStream);

填充" offer sdp "中缺失的属性;我使用了以下代码:

sdp = sdp.replace(/a=msid-semantic: WMS/g, 'a=msid-semantic: WMS ' + getChars());
sdp = sdp.replace(/recvonly/g, 'sendrecv')
var chars00 = getChars();
var numbers = getNumbers();
sdp += 'a=ssrc:'+ numbers+' cname:+Sb9HXiiNN/nhpZ1rn';
sdp += 'a=ssrc:'+ numbers+' msid:' + chars00 + ' v0rn';
sdp += 'a=ssrc:'+ numbers+' mslabel:' + chars00 + 'rn';
sdp += 'a=ssrc:'+ numbers+' label:' + chars00 + 'rn';
var replace = 'a=rtpmap:126 telephone-event/8000rn';
var chars00 = getChars();
var numbers = getNumbers();
replace += 'a=ssrc:'+ numbers+' cname:iecJoX+jqjkT8Dkyrn';
replace += 'a=ssrc:'+ numbers+' msid:' + chars00 + 'rn';
replace += 'a=ssrc:'+ numbers+' mslabel:' + chars00 + 'rn';
replace += 'a=ssrc:'+ numbers+' label:' + chars00;
sdp = sdp.replace(/a=rtpmap:126 telephone-event/8000/g, replace)

记住，" getChars "one_answers" getNumbers "方法返回的是随机值。

测试的演示