不能使用name()访问XSL哈希映射键

Question

我经常在xsl中使用棘手的哈希映射，但这次…我不知道该如何解决这个问题…

相关XML摘录:

<DOCUMENT>
  <PANO_LIV_MIN>True</PANO_LIV_MIN>
  <PANO_LIV_INTER>True</PANO_LIV_INTER>
  <!-- PANO_LIV_MATIN voluntarily ommited --> 
</DOCUMENT>

XSL的相关摘录:

  [...]
  <xsl:variable name="hashmap">
    <entry key="PANO_LIV_MATIN">Matin</entry>
    <entry key="PANO_LIV_MIN">Ministre</entry>
    <entry key="PANO_LIV_INTER">International</entry>
  </xsl:variable>
  <xsl:for-each select="PANO_LIV_MATIN[text() = 'True'] | PANO_LIV_MIN[text() = 'True'] | PANO_LIV_INTER[text() = 'True']">
    <span class="panorama">
      <xsl:value-of select="exsl:node-set($hashmap)/entry[@key=name()]" />*
      #<xsl:value-of select="name()"/>#
    </span>
  </xsl:for-each>
  [...]

结果:

<span class="panorama">* #PANO_LIV_MATIN#</span> - <span style="" class="panorama">* #PANO_LIV_MIN#</span>

预期结果:

<span class="panorama">Matin * #PANO_LIV_MATIN#</span> - <span style="" class="panorama">Ministre * #PANO_LIV_MIN#</span>

什么有效:

<xsl:value-of select="exsl:node-set($hashmap)/entry[@key='PANO_LIV_MATIN']" />
<!-- gives me Matin as expected -->

什么不工作，但我不知道为什么:

<xsl:value-of select="exsl:node-set($hashmap)/entry[@key=name()]" />
<!-- gives me nothing, but the name() print exactly the good key if I put it in a xsl:value-of -->

name()方法有什么问题?

Answer 1

在您的示例中name()的问题是，它是在错误的上下文节点，因为它在您的$hashmap上的选择中使用，您必须使用变量代替:

<xsl:for-each select="PANO_LIV_MATIN[text() = 'True'] | PANO_LIV_MIN[text() = 'True'] | PANO_LIV_INTER[text() = 'True']">
<xsl:variable name="name" select="name()"/>
<span class="panorama">
  <xsl:value-of select="exsl:node-set($hashmap)/entry[@key=$name]" />*
  #<xsl:value-of select="name()"/>#
</span>

Answer 2

你需要<xsl:value-of select="exsl:node-set($hashmap)/entry[@key = name(current())]" />