如果复选框已被选中，则退出应用程序

Question

我创建了一个脚本，通过使用听写命令"启用共享"来激活它，它会成功打开系统偏好/共享/然后它会自动点击复选框，无论它已经启用或禁用。

我想有两个听写命令，一个用于启用共享，一个用于禁用共享。我如何添加一个条件，当我说"启用共享"时，它会运行整个脚本，如果共享复选框已经被选中，只要退出系统偏好，而不是点击那个复选框，如果它已经被选中，实际上会取消选中那个复选框?

activate application "System Preferences"
delay 1
tell application "System Events"
    tell process "System Preferences"
        click button "Sharing" of scroll area 1 of window "System Preferences"
    end tell
end tell
activate application "System Preferences"
delay 1
tell application "System Events"
    tell process "System Preferences"
        click checkbox 1 of row 2 of table 1 of scroll area 1 of group 1 of window "Sharing"
    end tell
end tell
tell application "System Preferences"
quit
end tell

Answer 1

我帮你修好了。

activate application "System Preferences"
delay 1
tell application "System Events"
    tell process "System Preferences"
        click button "Sharing" of scroll area 1 of window "System Preferences"
    end tell
end tell
activate application "System Preferences"
delay 1
tell application "System Events"
    tell process "System Preferences"

        set theCheckbox to checkbox 1 of row 2 of table 1 of scroll area 1 of group 1 of window "Sharing"
        tell theCheckbox
            if false then click theCheckbox
        end tell

    end tell
end tell
tell application "System Preferences"
    quit
end tell

Answer 2

找到了!在尝试了各种不同的组合之后……

activate application "System Preferences"
delay 1
tell application "System Events"
    tell process "System Preferences"
        click button "Sharing" of scroll area 1 of window "System Preferences"
    end tell
end tell
activate application "System Preferences"
delay 1
tell application "System Events"
    tell process "System Preferences"
        tell checkbox 1 of row 2 of table 1 of scroll area 1 of group 1 of window "Sharing" to if value is 0 then click
        delay 1
    end tell
end tell
tell application "System Preferences"
     quit
end tell