Java 猜谜游戏运行,但无法正常运行



无法弄清楚我在java猜谜游戏中做错了什么。 计算机选取一个介于 1 和 100 之间的数字,并要求用户猜测它。 提示用户太低或太高,并要求用户再次猜测,直到他们正确为止。 我的问题是,当你猜对数字时,它总是会说太低,但如果你再次输入相同的数字,它会说正确。

package guessinggame;
import java.util.Scanner;
/**
 *
 * @author
 */
public class GuessingGame {
    /**
     * @param args the command line arguments
     */
    public static void main(String[] args)
    {
        Scanner input = new Scanner (System.in);
        int guesses;    //number of users guesses
        int housePick;  //number the user must guess
        int guess;      //users guess
        guesses = 0;
        housePick = (int)((Math.random() * 100) +1 );  
        //sets housePick to random number from 1 to 100
        System.out.println("I'm thinking of a number between 1 and 100") ;
        //print "Im thinking of a nubmer between 1 and 100"
        System.out.println("Can you guess what it is?");
        //print "can you guess what it is"
        System.out.println
                ("Enter a number from 1 to 100 (including 1 and 100)");
        //prompt user to enter number
        System.out.println("test " +housePick );
        //Test: tells user the correct answer
        do
        {
            guess = input.nextInt();
            if (guess > housePick)  //and if guess > housePick...
            {
                if ((guess - 10) <= housePick )  
                    //and if guess is 10 numbers away from housePick...
                {
                    System.out.println("Close, but too high. Try again.");
                    //print "close but too high, try again"
                    guesses = guesses+ 1 ;

                }
                else              //if guess is not close and guess>housePick...
                {
                    System.out.println ("Too high, try again.");  
                    //then print "Too high, Try again"
                    guesses = guesses+ 1;

                }                         
            }
            else  //If guess<housePick
            {
            if ((guess + 10) >= housePick)  //AND if guess is close to housePick
            {
                System.out.println ("close, but too low.") ; 
                //then print "close, but too low"
                guesses = guesses + 1;
            }
            else//If guess isnt close to housePick and is less than housePick...
            {
                guesses = guesses+ 1;
                System.out.println ("Too low.");//then print "too low"
            }
            }
        }while (guess != housePick);  //while guess doesnt = housePick...
          guess = input.nextInt();
        //save entered number as guess
    guesses = guesses + 1;
        System.out.println ("You win!  It took you "  +  guesses + " guesses.");
        //If guess = housePick print "Yout win! It took you (# of guesses)"


    }
}
else  //If guess<housePick

你错了上面的条件,它相当于guess <= housePick。 它必须是

else if( guess < housePick)

另外,以下代码块是在housePick == guess时执行的,所以没有做guess = input.nextInt()的意义,你可以简单地说你赢了。

}while (guess != housePick);  //while guess doesnt = housePick...
  // At this point, guess == housePick, why ask for input again????
        //  guess = input.nextInt(); 
        //save entered number as guess
    //guesses = guesses + 1;

在 while 之后,你还有一个额外的 input.nextInt((:

}while (guess != housePick);  //while guess doesnt = housePick...
guess = input.nextInt();
//save entered number as guess

删除它

让我们看看

家选 = 87

猜测 = 87

if ((guess + 10) >= housePick)  //AND if guess is close to housePick
{
       System.out.println ("close, but too low.") ; 
       //then print "close, but too low"
       guesses = guesses + 1;
}

嗯 87 + 10 大于 87

然后它中断了 do/while 循环,并再次提示您

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