Android StateListDrawable bug?

Question

i have StateListdrawable in xml

<selector xmlns:android="http://schemas.android.com/apk/res/android">
    <item android:state_activated="false" android:drawable="@drawable/ic_checked_off" />
    <item android:state_activated="true" android:drawable="@drawable/ic_checked_on" />
    <item android:drawable="@drawable/ic_checked_on" android:state_pressed="true" />
    <item android:drawable="@drawable/ic_checked_off" />
</selector>

我有GridView具有StateListDrawable的图像，并以编程方式尝试更改可绘制状态

    if(mSelected.contains(photo)){
        view.findViewById(R.id.selector).setActivated(true);
    }

选择的图像更改状态，但是当我单击他的状态不变时，对不起，我无法解释我想要什么，我的英语更差

我试着解释一下

如果我点击时mSelected.contains(photo) [state - active] -> [checked_on.jpg] ->状态可绘制对象从第一个开始，忽略我的编程状态更改

==

编辑==

适配器项目 --

private View getPhoto(int position, View convertView, ViewGroup parent){
        View view = convertView;
        if(convertView == null){
            view = LayoutInflater.from(mContext).inflate(R.layout.gallery_photo_item, parent, false);
        }
        ImageView mPhoto = (ImageView)view.findViewById(R.id.photoview);
        Photo photo = (Photo) getItem(position - COLUMNS_NUM);
        if(mSelected.contains(photo)){
            view.findViewById(R.id.selector).setActivated(true); // here i change my drawable state because it's front of my imageView
        }
        mLoader.displayImage(MediaStore.Images.Media.EXTERNAL_CONTENT_URI + File.separator + photo.id,
                mPhoto);
        return view;
    }

Answer 1

问题是状态的顺序。它们从上到下检查，并使用第一个符合情况的。因此，这意味着始终使用前两个。这应该有效：

<selector xmlns:android="http://schemas.android.com/apk/res/android">
    <item android:state_pressed="true" android:drawable="@drawable/ic_checked_on"  />
    <item android:state_activated="false" android:drawable="@drawable/ic_checked_off" />
    <item android:state_activated="true" android:drawable="@drawable/ic_checked_on" />
    <item android:drawable="@drawable/ic_checked_off" />
</selector>